Algebra Examples

$a_{n} = 6 {(2)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = 6 {(2)}^{(3) - 1}$

Step 2

Subtract $1$ from $3$ .

$a_{3} = 6 \cdot 2^{2}$

Step 3

Raise $2$ to the power of $2$ .

$a_{3} = 6 \cdot 4$

Step 4

Multiply $6$ by $4$ .

$a_{3} = 24$