Algebra Examples

$\sqrt{2} \sin (x) - 1 = 0$

Step 1

The degree cannot be determined because $\sqrt{2} \sin (x) - 1$ is not a polynomial.

Not a polynomial

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$