Algebra Examples

$4 (\cos (240 °) + i \sin (240 °))$

Step 1

Simplify each term.

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Step 1.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the third quadrant.

$4 (- \cos (60) + i \sin (240 °))$

Step 1.2

The exact value of $\cos (60)$ is $\frac{1}{2}$ .

$4 (- \frac{1}{2} + i \sin (240 °))$

Step 1.3

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because sine is negative in the third quadrant.

$4 (- \frac{1}{2} + i (- \sin (60)))$

Step 1.4

The exact value of $\sin (60)$ is $\frac{\sqrt{3}}{2}$ .

$4 (- \frac{1}{2} + i (- \frac{\sqrt{3}}{2}))$

Step 1.5

Combine $i$ and $\frac{\sqrt{3}}{2}$ .

$4 (- \frac{1}{2} - \frac{i \sqrt{3}}{2})$

Step 2

Simplify terms.

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Step 2.1

Apply the distributive property.

$4 (- \frac{1}{2}) + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.2

Cancel the common factor of $2$ .

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Step 2.2.1

Move the leading negative in $- \frac{1}{2}$ into the numerator.

$4 (\frac{- 1}{2}) + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.2.2

Factor $2$ out of $4$ .

$2 (2) \frac{- 1}{2} + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.2.3

Cancel the common factor.

$2 \cdot 2 \frac{- 1}{2} + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.2.4

Rewrite the expression.

$2 \cdot - 1 + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.3

Multiply $2$ by $- 1$ .

$- 2 + 4 (- \frac{i \sqrt{3}}{2})$

Step 2.4

Cancel the common factor of $2$ .

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Step 2.4.1

Move the leading negative in $- \frac{i \sqrt{3}}{2}$ into the numerator.

$- 2 + 4 \frac{- i \sqrt{3}}{2}$

Step 2.4.2

Factor $2$ out of $4$ .

$- 2 + 2 (2) \frac{- i \sqrt{3}}{2}$

Step 2.4.3

Cancel the common factor.

$- 2 + 2 \cdot 2 \frac{- i \sqrt{3}}{2}$

Step 2.4.4

Rewrite the expression.

$- 2 + 2 (- i \sqrt{3})$

Step 2.5

Multiply $- 1$ by $2$ .

$- 2 - 2 i \sqrt{3}$