Algebra Examples

$2 {(\cos (20) + i \sin (20))}^{3}$

Step 1

Use the Binomial Theorem.

$2 (\cos^{3} (20) + 3 \cos^{2} (20) (i \sin (20)) + 3 \cos (20) {(i \sin (20))}^{2} + {(i \sin (20))}^{3})$

Step 2

Simplify terms.

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the product rule to $i \sin (20)$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) + 3 \cos (20) (i^{2} \sin^{2} (20)) + {(i \sin (20))}^{3})$

Step 2.1.2

Rewrite $i^{2}$ as $- 1$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) + 3 \cos (20) (- 1 \sin^{2} (20)) + {(i \sin (20))}^{3})$

Step 2.1.3

Rewrite $- 1 \sin^{2} (20)$ as $- \sin^{2} (20)$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) + 3 \cos (20) (- \sin^{2} (20)) + {(i \sin (20))}^{3})$

Step 2.1.4

Multiply $- 1$ by $3$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) - 3 \cos (20) \sin^{2} (20) + {(i \sin (20))}^{3})$

Step 2.1.5

Apply the product rule to $i \sin (20)$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) - 3 \cos (20) \sin^{2} (20) + i^{3} \sin^{3} (20))$

Step 2.1.6

Factor out $i^{2}$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) - 3 \cos (20) \sin^{2} (20) + i^{2} \cdot i \sin^{3} (20))$

Step 2.1.7

Rewrite $i^{2}$ as $- 1$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) - 3 \cos (20) \sin^{2} (20) - 1 \cdot i \sin^{3} (20))$

Step 2.1.8

Rewrite $- 1 i$ as $- i$ .

$2 (\cos^{3} (20) + 3 \cos^{2} (20) i \sin (20) - 3 \cos (20) \sin^{2} (20) - i \sin^{3} (20))$

Step 2.2

Apply the distributive property.

$2 \cos^{3} (20) + 2 (3 \cos^{2} (20) i \sin (20)) + 2 (- 3 \cos (20) \sin^{2} (20)) + 2 (- i \sin^{3} (20))$

Step 3

Simplify.

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Step 3.1

Multiply $3$ by $2$ .

$2 \cos^{3} (20) + 6 (\cos^{2} (20) i \sin (20)) + 2 (- 3 \cos (20) \sin^{2} (20)) + 2 (- i \sin^{3} (20))$

Step 3.2

Multiply $- 3$ by $2$ .

$2 \cos^{3} (20) + 6 (\cos^{2} (20) i \sin (20)) - 6 (\cos (20) \sin^{2} (20)) + 2 (- i \sin^{3} (20))$

Step 3.3

Multiply $- 1$ by $2$ .

$2 \cos^{3} (20) + 6 (\cos^{2} (20) i \sin (20)) - 6 (\cos (20) \sin^{2} (20)) - 2 (i \sin^{3} (20))$

Step 4

Remove parentheses.

$2 \cos^{3} (20) + 6 \cos^{2} (20) i \sin (20) - 6 \cos (20) \sin^{2} (20) - 2 i \sin^{3} (20)$

Step 5

Simplify the expression.

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Step 5.1

Reorder factors in $2 \cos^{3} (20) + 6 \cos^{2} (20) i \sin (20) - 6 \cos (20) \sin^{2} (20) - 2 i \sin^{3} (20)$ .

$2 \cos^{3} (20) + 6 i \cos^{2} (20) \sin (20) - 6 \cos (20) \sin^{2} (20) - 2 i \sin^{3} (20)$

Step 5.2

Reorder $2 \cos^{3} (20) + 6 i \cos^{2} (20) \sin (20)$ and $- 6 \cos (20) \sin^{2} (20)$ .

$- 6 \cos (20) \sin^{2} (20) + 2 \cos^{3} (20) + 6 i \cos^{2} (20) \sin (20) - 2 i \sin^{3} (20)$