Algebra Examples

$- \frac{1}{16} {(2)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = - \frac{1}{16} \cdot {(2)}^{(3) - 1}$

Step 2

Simplify the expression.

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Step 2.1

Subtract $1$ from $3$ .

$a_{3} = - \frac{1}{16} \cdot 2^{2}$

Step 2.2

Raise $2$ to the power of $2$ .

$a_{3} = - \frac{1}{16} \cdot 4$

Step 3

Cancel the common factor of $4$ .

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Step 3.1

Move the leading negative in $- \frac{1}{16}$ into the numerator.

$a_{3} = \frac{- 1}{16} \cdot 4$

Step 3.2

Factor $4$ out of $16$ .

$a_{3} = \frac{- 1}{4 (4)} \cdot 4$

Step 3.3

Cancel the common factor.

$a_{3} = \frac{- 1}{4 \cdot 4} \cdot 4$

Step 3.4

Rewrite the expression.

$a_{3} = \frac{- 1}{4}$

Step 4

Move the negative in front of the fraction.

$a_{3} = - \frac{1}{4}$