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Convert from Interval to Inequality (1,100) union (1,9)

$(1, 100) \cup (1, 9)$

Step 1

The inequality form is $1 < x < 100$ .

$1 < x < 100$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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