Algebra Examples

$\frac{(3 x + 2 x^{3} - 9 - 8 x^{2})}{(x^{2} + 1)}$

Step 1

Expand $3 x + 2 x^{3} - 9 - 8 x^{2}$ .

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Step 1.1

Reorder $3 x$ and $2 x^{3}$ .

$\frac{2 x^{3} + 3 x - 9 - 8 x^{2}}{x^{2} + 1}$

Step 1.2

Move $- 9$ .

$\frac{2 x^{3} + 3 x - 8 x^{2} - 9}{x^{2} + 1}$

Step 1.3

Move $3 x$ .

$\frac{2 x^{3} - 8 x^{2} + 3 x - 9}{x^{2} + 1}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$0 x$

$1$

$2 x^{3}$

$8 x^{2}$

$3 x$

$9$

Step 3

Divide the highest order term in the dividend $2 x^{3}$ by the highest order term in divisor $x^{2}$ .

$2 x$

$x^{2}$

$0 x$

$1$

$2 x^{3}$

$8 x^{2}$

$3 x$

$9$

Step 4

Multiply the new quotient term by the divisor.

$2 x$

$x^{2}$

$0 x$

$1$

$2 x^{3}$

$8 x^{2}$

$3 x$

$9$

$2 x^{3}$

$0$

$2 x$

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{3} + 0 + 2 x$

						$2 x$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x$

$x^{2}$

$0 x$

$1$

$2 x^{3}$

$8 x^{2}$

$3 x$

$9$

$2 x^{3}$

$0$

$2 x$

$8 x^{2}$

$x$

Step 7

Pull the next terms from the original dividend down into the current dividend.

						$2 x$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$
							-	$8 x^{2}$	+	$x$	-	$9$

Step 8

Divide the highest order term in the dividend $- 8 x^{2}$ by the highest order term in divisor $x^{2}$ .

						$2 x$	-	$8$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$
							-	$8 x^{2}$	+	$x$	-	$9$

Step 9

Multiply the new quotient term by the divisor.

						$2 x$	-	$8$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$
							-	$8 x^{2}$	+	$x$	-	$9$
							-	$8 x^{2}$	+	$0$	-	$8$

Step 10

The expression needs to be subtracted from the dividend, so change all the signs in $- 8 x^{2} + 0 - 8$

						$2 x$	-	$8$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$
							-	$8 x^{2}$	+	$x$	-	$9$
							+	$8 x^{2}$	-	$0$	+	$8$

Step 11

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

						$2 x$	-	$8$
$x^{2}$	+	$0 x$	+	$1$		$2 x^{3}$	-	$8 x^{2}$	+	$3 x$	-	$9$
					-	$2 x^{3}$	-	$0$	-	$2 x$
							-	$8 x^{2}$	+	$x$	-	$9$
							+	$8 x^{2}$	-	$0$	+	$8$
									+	$x$	-	$1$

Step 12

The final answer is the quotient plus the remainder over the divisor.

$2 x - 8 + \frac{x - 1}{x^{2} + 1}$