Algebra Examples

$\frac{(- 16 x^{3} - 28 x^{2} - 6 x + 7)}{(4 x + 5)}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$4 x$

$5$

$16 x^{3}$

$28 x^{2}$

$6 x$

$7$

Step 2

Divide the highest order term in the dividend $- 16 x^{3}$ by the highest order term in divisor $4 x$ .

				-	$4 x^{2}$
	$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$

Step 3

Multiply the new quotient term by the divisor.

			-	$4 x^{2}$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			-	$16 x^{3}$	-	$20 x^{2}$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $- 16 x^{3} - 20 x^{2}$

			-	$4 x^{2}$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$4 x^{2}$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$

Step 6

Pull the next terms from the original dividend down into the current dividend.

			-	$4 x^{2}$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$

Step 7

Divide the highest order term in the dividend $- 8 x^{2}$ by the highest order term in divisor $4 x$ .

			-	$4 x^{2}$	-	$2 x$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$

Step 8

Multiply the new quotient term by the divisor.

			-	$4 x^{2}$	-	$2 x$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					-	$8 x^{2}$	-	$10 x$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $- 8 x^{2} - 10 x$

			-	$4 x^{2}$	-	$2 x$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$4 x^{2}$	-	$2 x$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$

Step 11

Pull the next terms from the original dividend down into the current dividend.

			-	$4 x^{2}$	-	$2 x$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$	+	$7$

Step 12

Divide the highest order term in the dividend $4 x$ by the highest order term in divisor $4 x$ .

			-	$4 x^{2}$	-	$2 x$	+	$1$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$	+	$7$

Step 13

Multiply the new quotient term by the divisor.

			-	$4 x^{2}$	-	$2 x$	+	$1$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$	+	$7$
							+	$4 x$	+	$5$

Step 14

The expression needs to be subtracted from the dividend, so change all the signs in $4 x + 5$

			-	$4 x^{2}$	-	$2 x$	+	$1$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$	+	$7$
							-	$4 x$	-	$5$

Step 15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$4 x^{2}$	-	$2 x$	+	$1$
$4 x$	+	$5$	-	$16 x^{3}$	-	$28 x^{2}$	-	$6 x$	+	$7$
			+	$16 x^{3}$	+	$20 x^{2}$
					-	$8 x^{2}$	-	$6 x$
					+	$8 x^{2}$	+	$10 x$
							+	$4 x$	+	$7$
							-	$4 x$	-	$5$
									+	$2$

Step 16

The final answer is the quotient plus the remainder over the divisor.

$- 4 x^{2} - 2 x + 1 + \frac{2}{4 x + 5}$