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Convert from Interval to Inequality (negative infinity,8) union (negative infinity,11)

$(- \infty, 8) \cup (- \infty, 11)$

Step 1

The inequality form is $x < 11$ .

$x < 11$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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