Algebra Examples

$f (x) = x^{3} - 6$ , $g (x) = \sqrt[3]{x + 6}$

Step 1

Set up the composite result function.

$g (f (x))$

Step 2

Evaluate $g (x^{3} - 6)$ by substituting in the value of $f$ into $g$ .

$g (x^{3} - 6) = \sqrt[3]{(x^{3} - 6) + 6}$

Step 3

Add $- 6$ and $6$ .

$g (x^{3} - 6) = \sqrt[3]{x^{3} + 0}$

Step 4

Add $x^{3}$ and $0$ .

$g (x^{3} - 6) = \sqrt[3]{x^{3}}$

Step 5

Pull terms out from under the radical, assuming real numbers.

$g (x^{3} - 6) = x$