Algebra Examples

$f (x) = \sqrt{x - 1}$ ; $g (x) = 2 x - 7$

Step 1

Set up the composite result function.

$f (g (x))$

Step 2

Evaluate $f (2 x - 7)$ by substituting in the value of $g$ into $f$ .

$f (2 x - 7) = \sqrt{(2 x - 7) - 1}$

Step 3

Subtract $1$ from $- 7$ .

$f (2 x - 7) = \sqrt{2 x - 8}$

Step 4

Factor $2$ out of $2 x - 8$ .

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Step 4.1

Factor $2$ out of $2 x$ .

$f (2 x - 7) = \sqrt{2 (x) - 8}$

Step 4.2

Factor $2$ out of $- 8$ .

$f (2 x - 7) = \sqrt{2 x + 2 \cdot - 4}$

Step 4.3

Factor $2$ out of $2 x + 2 \cdot - 4$ .

$f (2 x - 7) = \sqrt{2 (x - 4)}$