Algebra Examples

$x (5 - 2 x) + 15 = 0$

Step 1

Simplify the left side.

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$x \cdot 5 + x (- 2 x) + 15 = 0$

Step 1.1.2

Move $5$ to the left of $x$ .

$5 \cdot x + x (- 2 x) + 15 = 0$

Step 1.1.3

Rewrite using the commutative property of multiplication.

$5 \cdot x - 2 x \cdot x + 15 = 0$

Step 1.1.4

Multiply $x$ by $x$ by adding the exponents.

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Step 1.1.4.1

Move $x$ .

$5 x - 2 (x \cdot x) + 15 = 0$

Step 1.1.4.2

Multiply $x$ by $x$ .

$5 x - 2 x^{2} + 15 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 2$ , $b = 5$ , $c = 15$