Algebra Examples

$| x - 8 | < - 10$

Step 1

Since $| x - 8 |$ is always positive and $- 10$ is negative, $| x - 8 |$ is always greater than $- 10$ so the inequality cannot be true.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$