Algebra Examples

$a + 3 b = 10$

Step 1

Subtract $3 b$ from both sides of the equation.

$a = 10 - 3 b$

Step 2

Choose any value for $b$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $b$ to find the ordered pair.

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Step 3.1

Simplify $10 - 3 \cdot 0$ .

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Step 3.1.1

Multiply $- 3$ by $0$ .

$a = 10 + 0$

Step 3.1.2

Add $10$ and $0$ .

$a = 10$

Step 3.2

Use the $b$ and $y$ values to form the ordered pair.

$(0, 10)$

Step 4

Choose $1$ to substitute in for $b$ to find the ordered pair.

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Step 4.1

Simplify $10 - 3 \cdot 1$ .

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Step 4.1.1

Multiply $- 3$ by $1$ .

$a = 10 - 3$

Step 4.1.2

Subtract $3$ from $10$ .

$a = 7$

Step 4.2

Use the $b$ and $y$ values to form the ordered pair.

$(1, 7)$

Step 5

Choose $2$ to substitute in for $b$ to find the ordered pair.

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Step 5.1

Simplify $10 - 3 \cdot 2$ .

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Step 5.1.1

Multiply $- 3$ by $2$ .

$a = 10 - 6$

Step 5.1.2

Subtract $6$ from $10$ .

$a = 4$

Step 5.2

Use the $b$ and $y$ values to form the ordered pair.

$(2, 4)$

Step 6

These are three possible solutions to the equation.

$(0, 10), (1, 7), (2, 4)$

Step 7