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Algebra Examples

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Find the Vertex Form y=2(x+4)^2+5

$y = 2 {(x + 4)}^{2} + 5$

Step 1

Already in vertex form.

$y = 2 {(x + 4)}^{2} + 5$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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