Algebra Examples

$4 b - 1 = - 4 + 4 b + 3$

Step 1

Move all the expressions to the left side of the equation.

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Step 1.1

Add $4$ to both sides of the equation.

$4 b - 1 + 4 = 4 b + 3$

Step 1.2

Subtract $4 b$ from both sides of the equation.

$4 b - 1 + 4 - 4 b = 3$

Step 1.3

Subtract $3$ from both sides of the equation.

$4 b - 1 + 4 - 4 b - 3 = 0$

Step 2

Simplify $4 b - 1 + 4 - 4 b - 3$ .

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Step 2.1

Combine the opposite terms in $4 b - 1 + 4 - 4 b - 3$ .

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Step 2.1.1

Subtract $4 b$ from $4 b$ .

$0 - 1 + 4 - 3 = 0$

Step 2.1.2

Subtract $1$ from $0$ .

$- 1 + 4 - 3 = 0$

Step 2.2

Add $- 1$ and $4$ .

$3 - 3 = 0$

Step 2.3

Subtract $3$ from $3$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true