Algebra Examples

$a = \frac{1}{4} \cdot (b + c)$

Step 1

Rewrite the equation as $\frac{1}{4} \cdot (b + c) = a$ .

$\frac{1}{4} \cdot (b + c) = a$

Step 2

Multiply both sides of the equation by $4$ .

$4 (\frac{1}{4} \cdot (b + c)) = 4 a$

Step 3

Simplify the left side.

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Step 3.1

Simplify $4 (\frac{1}{4} \cdot (b + c))$ .

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Step 3.1.1

Apply the distributive property.

$4 (\frac{1}{4} b + \frac{1}{4} c) = 4 a$

Step 3.1.2

Combine $\frac{1}{4}$ and $b$ .

$4 (\frac{b}{4} + \frac{1}{4} c) = 4 a$

Step 3.1.3

Combine $\frac{1}{4}$ and $c$ .

$4 (\frac{b}{4} + \frac{c}{4}) = 4 a$

Step 3.1.4

Apply the distributive property.

$4 \frac{b}{4} + 4 \frac{c}{4} = 4 a$

Step 3.1.5

Cancel the common factor of $4$ .

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Step 3.1.5.1

Cancel the common factor.

$4 \frac{b}{4} + 4 \frac{c}{4} = 4 a$

Step 3.1.5.2

Rewrite the expression.

$b + 4 \frac{c}{4} = 4 a$

$b + 4 \frac{c}{4} = 4 a$

Step 3.1.6

Cancel the common factor of $4$ .

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Step 3.1.6.1

Cancel the common factor.

$b + 4 \frac{c}{4} = 4 a$

Step 3.1.6.2

Rewrite the expression.

$b + c = 4 a$

$b + c = 4 a$

$b + c = 4 a$

$b + c = 4 a$

Step 4

Subtract $b$ from both sides of the equation.

$c = 4 a - b$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$