Algebra Examples

$\frac{1}{8} \cdot \ln (y) + \ln (z)$

Step 1

Simplify $\frac{1}{8} \ln (y)$ by moving $\frac{1}{8}$ inside the logarithm.

$\ln (y^{\frac{1}{8}}) + \ln (z)$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\ln (y^{\frac{1}{8}} z)$

Step 3

Reorder factors in $\ln (y^{\frac{1}{8}} z)$ .

$\ln (z y^{\frac{1}{8}})$