Algebra Examples

$3 + {(4 - x)}^{\frac{3}{2}} = 11$

Step 1

Subtract $11$ from both sides of the equation.

$3 + {(4 - x)}^{\frac{3}{2}} - 11 = 0$

Step 2

Subtract $11$ from $3$ .

$- 8 + {(4 - x)}^{\frac{3}{2}} = 0$

Step 3

Rewrite $- 8$ as ${(- 2)}^{3}$ .

${(- 2)}^{3} + {(4 - x)}^{\frac{3}{2}} = 0$

Step 4

Rewrite ${(4 - x)}^{\frac{3}{2}}$ as ${({(4 - x)}^{\frac{1}{2}})}^{3}$ .

${(- 2)}^{3} + {({(4 - x)}^{\frac{1}{2}})}^{3} = 0$

Step 5

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = - 2$ and $b = {(4 - x)}^{\frac{1}{2}}$ .

$(- 2 + {(4 - x)}^{\frac{1}{2}}) ({(- 2)}^{2} + 2 {(4 - x)}^{\frac{1}{2}} + {({(4 - x)}^{\frac{1}{2}})}^{2}) = 0$

Step 6

Simplify.

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Step 6.1

Raise $- 2$ to the power of $2$ .

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (4 + 2 {(4 - x)}^{\frac{1}{2}} + {({(4 - x)}^{\frac{1}{2}})}^{2}) = 0$

Step 6.2

Multiply the exponents in ${({(4 - x)}^{\frac{1}{2}})}^{2}$ .

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Step 6.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (4 + 2 {(4 - x)}^{\frac{1}{2}} + {(4 - x)}^{\frac{1}{2} \cdot 2}) = 0$

Step 6.2.2

Cancel the common factor of $2$ .

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Step 6.2.2.1

Cancel the common factor.

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (4 + 2 {(4 - x)}^{\frac{1}{2}} + {(4 - x)}^{\frac{1}{2} \cdot 2}) = 0$

Step 6.2.2.2

Rewrite the expression.

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (4 + 2 {(4 - x)}^{\frac{1}{2}} + 4 - x) = 0$

Step 6.3

Simplify.

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (4 + 2 {(4 - x)}^{\frac{1}{2}} + 4 - x) = 0$

Step 6.4

Add $4$ and $4$ .

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (2 {(4 - x)}^{\frac{1}{2}} + 8 - x) = 0$

Step 6.5

Reorder terms.

$(- 2 + {(4 - x)}^{\frac{1}{2}}) (- x + 2 {(4 - x)}^{\frac{1}{2}} + 8) = 0$

Step 7

Simplify $(- 2 + {(4 - x)}^{\frac{1}{2}}) (- x + 2 {(4 - x)}^{\frac{1}{2}} + 8)$ .

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Step 7.1

Expand $(- 2 + {(4 - x)}^{\frac{1}{2}}) (- x + 2 {(4 - x)}^{\frac{1}{2}} + 8)$ by multiplying each term in the first expression by each term in the second expression.

$- 2 (- x) - 2 (2 {(4 - x)}^{\frac{1}{2}}) - 2 \cdot 8 + {(4 - x)}^{\frac{1}{2}} (- x) + {(4 - x)}^{\frac{1}{2}} (2 {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2

Simplify terms.

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Step 7.2.1

Simplify each term.

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Step 7.2.1.1

Multiply $- 1$ by $- 2$ .

$2 x - 2 (2 {(4 - x)}^{\frac{1}{2}}) - 2 \cdot 8 + {(4 - x)}^{\frac{1}{2}} (- x) + {(4 - x)}^{\frac{1}{2}} (2 {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.2

Multiply $2$ by $- 2$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 2 \cdot 8 + {(4 - x)}^{\frac{1}{2}} (- x) + {(4 - x)}^{\frac{1}{2}} (2 {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.3

Multiply $- 2$ by $8$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 + {(4 - x)}^{\frac{1}{2}} (- x) + {(4 - x)}^{\frac{1}{2}} (2 {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.4

Rewrite using the commutative property of multiplication.

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + {(4 - x)}^{\frac{1}{2}} (2 {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.5

Rewrite using the commutative property of multiplication.

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 {(4 - x)}^{\frac{1}{2}} {(4 - x)}^{\frac{1}{2}} + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.6

Multiply ${(4 - x)}^{\frac{1}{2}}$ by ${(4 - x)}^{\frac{1}{2}}$ by adding the exponents.

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Step 7.2.1.6.1

Move ${(4 - x)}^{\frac{1}{2}}$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 ({(4 - x)}^{\frac{1}{2}} {(4 - x)}^{\frac{1}{2}}) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.6.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 {(4 - x)}^{\frac{1}{2} + \frac{1}{2}} + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.6.3

Combine the numerators over the common denominator.

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 {(4 - x)}^{\frac{1 + 1}{2}} + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.6.4

Add $1$ and $1$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 {(4 - x)}^{\frac{2}{2}} + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.6.5

Divide $2$ by $2$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 {(4 - x)}^{1} + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.7

Simplify $2 {(4 - x)}^{1}$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 (4 - x) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.8

Apply the distributive property.

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 2 \cdot 4 + 2 (- x) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.9

Multiply $2$ by $4$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 + 2 (- x) + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.10

Multiply $- 1$ by $2$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 - 2 x + {(4 - x)}^{\frac{1}{2}} \cdot 8 = 0$

Step 7.2.1.11

Move $8$ to the left of ${(4 - x)}^{\frac{1}{2}}$ .

$2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 - 2 x + 8 {(4 - x)}^{\frac{1}{2}} = 0$

Step 7.2.2

Simplify by adding terms.

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Step 7.2.2.1

Combine the opposite terms in $2 x - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 - 2 x + 8 {(4 - x)}^{\frac{1}{2}}$ .

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Step 7.2.2.1.1

Subtract $2 x$ from $2 x$ .

$0 - 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 + 8 {(4 - x)}^{\frac{1}{2}} = 0$

Step 7.2.2.1.2

Subtract $4 {(4 - x)}^{\frac{1}{2}}$ from $0$ .

$- 4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 + 8 {(4 - x)}^{\frac{1}{2}} = 0$

Step 7.2.2.2

Add $- 4 {(4 - x)}^{\frac{1}{2}}$ and $8 {(4 - x)}^{\frac{1}{2}}$ .

$4 {(4 - x)}^{\frac{1}{2}} - 16 - {(4 - x)}^{\frac{1}{2}} x + 8 = 0$

Step 7.2.2.3

Simplify the expression.

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Step 7.2.2.3.1

Add $- 16$ and $8$ .

$4 {(4 - x)}^{\frac{1}{2}} - {(4 - x)}^{\frac{1}{2}} x - 8 = 0$

Step 7.2.2.3.2

Reorder factors in $4 {(4 - x)}^{\frac{1}{2}} - {(4 - x)}^{\frac{1}{2}} x - 8$ .

$4 {(4 - x)}^{\frac{1}{2}} - x {(4 - x)}^{\frac{1}{2}} - 8 = 0$

Step 8

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x = 0$

Step 9