Algebra Examples

$2 (x - \frac{1}{3}) - \frac{3}{2} (y - \frac{1}{6}) = 0$ $3 (y - \frac{1}{2}) + \frac{8}{3} (x - \frac{1}{6}) = 0$

Step 1

Solve for $x$ in $2 (x - \frac{1}{3}) - \frac{3 y}{2} + \frac{1}{4} = 0$ .

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Step 1.1

Simplify $2 (x - \frac{1}{3}) - \frac{3 y}{2} + \frac{1}{4}$ .

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Step 1.1.1

Simplify each term.

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Step 1.1.1.1

Apply the distributive property.

$2 x + 2 (- \frac{1}{3}) - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.1.2

Multiply $2 (- \frac{1}{3})$ .

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Step 1.1.1.2.1

Multiply $- 1$ by $2$ .

$2 x - 2 (\frac{1}{3}) - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.1.2.2

Combine $- 2$ and $\frac{1}{3}$ .

$2 x + \frac{- 2}{3} - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x + \frac{- 2}{3} - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.1.3

Move the negative in front of the fraction.

$2 x - \frac{2}{3} - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x - \frac{2}{3} - \frac{3 y}{2} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.2

To write $- \frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$2 x - \frac{3 y}{2} - \frac{2}{3} \cdot \frac{4}{4} + \frac{1}{4} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.3

To write $\frac{1}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 x - \frac{3 y}{2} - \frac{2}{3} \cdot \frac{4}{4} + \frac{1}{4} \cdot \frac{3}{3} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.4

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.1.4.1

Multiply $\frac{2}{3}$ by $\frac{4}{4}$ .

$2 x - \frac{3 y}{2} - \frac{2 \cdot 4}{3 \cdot 4} + \frac{1}{4} \cdot \frac{3}{3} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.4.2

Multiply $3$ by $4$ .

$2 x - \frac{3 y}{2} - \frac{2 \cdot 4}{12} + \frac{1}{4} \cdot \frac{3}{3} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.4.3

Multiply $\frac{1}{4}$ by $\frac{3}{3}$ .

$2 x - \frac{3 y}{2} - \frac{2 \cdot 4}{12} + \frac{3}{4 \cdot 3} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.4.4

Multiply $4$ by $3$ .

$2 x - \frac{3 y}{2} - \frac{2 \cdot 4}{12} + \frac{3}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x - \frac{3 y}{2} - \frac{2 \cdot 4}{12} + \frac{3}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.5

Combine the numerators over the common denominator.

$2 x - \frac{3 y}{2} + \frac{- 2 \cdot 4 + 3}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.6

Simplify the numerator.

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Step 1.1.6.1

Multiply $- 2$ by $4$ .

$2 x - \frac{3 y}{2} + \frac{- 8 + 3}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.6.2

Add $- 8$ and $3$ .

$2 x - \frac{3 y}{2} + \frac{- 5}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x - \frac{3 y}{2} + \frac{- 5}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.1.7

Move the negative in front of the fraction.

$2 x - \frac{3 y}{2} - \frac{5}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x - \frac{3 y}{2} - \frac{5}{12} = 0$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.2

Move all terms not containing $x$ to the right side of the equation.

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Step 1.2.1

Add $\frac{3 y}{2}$ to both sides of the equation.

$2 x - \frac{5}{12} = \frac{3 y}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.2.2

Add $\frac{5}{12}$ to both sides of the equation.

$2 x = \frac{3 y}{2} + \frac{5}{12}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$2 x = \frac{3 y}{2} + \frac{5}{12}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3

Divide each term in $2 x = \frac{3 y}{2} + \frac{5}{12}$ by $2$ and simplify.

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Step 1.3.1

Divide each term in $2 x = \frac{3 y}{2} + \frac{5}{12}$ by $2$ .

$\frac{2 x}{2} = \frac{\frac{3 y}{2}}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.2

Simplify the left side.

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Step 1.3.2.1

Cancel the common factor of $2$ .

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Step 1.3.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{\frac{3 y}{2}}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.2.1.2

Divide $x$ by $1$ .

$x = \frac{\frac{3 y}{2}}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{\frac{3 y}{2}}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{\frac{3 y}{2}}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3

Simplify the right side.

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Step 1.3.3.1

Simplify each term.

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Step 1.3.3.1.1

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{3 y}{2} \cdot \frac{1}{2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3.1.2

Multiply $\frac{3 y}{2} \cdot \frac{1}{2}$ .

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Step 1.3.3.1.2.1

Multiply $\frac{3 y}{2}$ by $\frac{1}{2}$ .

$x = \frac{3 y}{2 \cdot 2} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3.1.2.2

Multiply $2$ by $2$ .

$x = \frac{3 y}{4} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{\frac{5}{12}}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3.1.3

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{3 y}{4} + \frac{5}{12} \cdot \frac{1}{2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3.1.4

Multiply $\frac{5}{12} \cdot \frac{1}{2}$ .

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Step 1.3.3.1.4.1

Multiply $\frac{5}{12}$ by $\frac{1}{2}$ .

$x = \frac{3 y}{4} + \frac{5}{12 \cdot 2}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 1.3.3.1.4.2

Multiply $12$ by $2$ .

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$

Step 2

Replace all occurrences of $x$ with $\frac{3 y}{4} + \frac{5}{24}$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $3 (y - \frac{1}{2}) + \frac{8 x}{3} - \frac{4}{9} = 0$ with $\frac{3 y}{4} + \frac{5}{24}$ .

$3 (y - \frac{1}{2}) + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $3 (y - \frac{1}{2}) + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} - \frac{4}{9}$ .

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Step 2.2.1.1

Find the common denominator.

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Step 2.2.1.1.1

Write $3 (y - \frac{1}{2})$ as a fraction with denominator $1$ .

$\frac{3 (y - \frac{1}{2})}{1} + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.1.2

Multiply $\frac{3 (y - \frac{1}{2})}{1}$ by $\frac{9}{9}$ .

$\frac{3 (y - \frac{1}{2})}{1} \cdot \frac{9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.1.3

Multiply $\frac{3 (y - \frac{1}{2})}{1}$ by $\frac{9}{9}$ .

$\frac{3 (y - \frac{1}{2}) \cdot 9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.1.4

Multiply $\frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3}$ by $\frac{3}{3}$ .

$\frac{3 (y - \frac{1}{2}) \cdot 9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3} \cdot \frac{3}{3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.1.5

Multiply $\frac{8 (\frac{3 y}{4} + \frac{5}{24})}{3}$ by $\frac{3}{3}$ .

$\frac{3 (y - \frac{1}{2}) \cdot 9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3}{3 \cdot 3} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.1.6

Multiply $3$ by $3$ .

$\frac{3 (y - \frac{1}{2}) \cdot 9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3}{9} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{3 (y - \frac{1}{2}) \cdot 9}{9} + \frac{8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3}{9} - \frac{4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.2

Combine the numerators over the common denominator.

$\frac{3 (y - \frac{1}{2}) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3

Simplify each term.

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Step 2.2.1.3.1

Apply the distributive property.

$\frac{(3 y + 3 (- \frac{1}{2})) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.2

Multiply $3 (- \frac{1}{2})$ .

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Step 2.2.1.3.2.1

Multiply $- 1$ by $3$ .

$\frac{(3 y - 3 (\frac{1}{2})) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.2.2

Combine $- 3$ and $\frac{1}{2}$ .

$\frac{(3 y + \frac{- 3}{2}) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{(3 y + \frac{- 3}{2}) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.3

Move the negative in front of the fraction.

$\frac{(3 y - \frac{3}{2}) \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.4

Apply the distributive property.

$\frac{3 y \cdot 9 - \frac{3}{2} \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.5

Multiply $9$ by $3$ .

$\frac{27 y - \frac{3}{2} \cdot 9 + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.6

Multiply $- \frac{3}{2} \cdot 9$ .

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Step 2.2.1.3.6.1

Multiply $9$ by $- 1$ .

$\frac{27 y - 9 (\frac{3}{2}) + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.6.2

Combine $- 9$ and $\frac{3}{2}$ .

$\frac{27 y + \frac{- 9 \cdot 3}{2} + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.6.3

Multiply $- 9$ by $3$ .

$\frac{27 y + \frac{- 27}{2} + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{27 y + \frac{- 27}{2} + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.7

Move the negative in front of the fraction.

$\frac{27 y - \frac{27}{2} + 8 (\frac{3 y}{4} + \frac{5}{24}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.8

Apply the distributive property.

$\frac{27 y - \frac{27}{2} + (8 (\frac{3 y}{4}) + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.9

Cancel the common factor of $4$ .

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Step 2.2.1.3.9.1

Factor $4$ out of $8$ .

$\frac{27 y - \frac{27}{2} + (4 (2) (\frac{3 y}{4}) + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.9.2

Cancel the common factor.

$\frac{27 y - \frac{27}{2} + (4 \cdot (2 (\frac{3 y}{4})) + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.9.3

Rewrite the expression.

$\frac{27 y - \frac{27}{2} + (2 (3 y) + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{27 y - \frac{27}{2} + (2 (3 y) + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.10

Multiply $3$ by $2$ .

$\frac{27 y - \frac{27}{2} + (6 y + 8 (\frac{5}{24})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.11

Cancel the common factor of $8$ .

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Step 2.2.1.3.11.1

Factor $8$ out of $24$ .

$\frac{27 y - \frac{27}{2} + (6 y + 8 (\frac{5}{8 (3)})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.11.2

Cancel the common factor.

$\frac{27 y - \frac{27}{2} + (6 y + 8 (\frac{5}{8 \cdot 3})) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.11.3

Rewrite the expression.

$\frac{27 y - \frac{27}{2} + (6 y + \frac{5}{3}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{27 y - \frac{27}{2} + (6 y + \frac{5}{3}) \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.12

Apply the distributive property.

$\frac{27 y - \frac{27}{2} + 6 y \cdot 3 + \frac{5}{3} \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.13

Multiply $3$ by $6$ .

$\frac{27 y - \frac{27}{2} + 18 y + \frac{5}{3} \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.14

Cancel the common factor of $3$ .

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Step 2.2.1.3.14.1

Cancel the common factor.

$\frac{27 y - \frac{27}{2} + 18 y + \frac{5}{3} \cdot 3 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.3.14.2

Rewrite the expression.

$\frac{27 y - \frac{27}{2} + 18 y + 5 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{27 y - \frac{27}{2} + 18 y + 5 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{27 y - \frac{27}{2} + 18 y + 5 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.4

Add $27 y$ and $18 y$ .

$\frac{45 y - \frac{27}{2} + 5 - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.5

To write $5$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{45 y - \frac{27}{2} + 5 \cdot \frac{2}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.6

Combine $5$ and $\frac{2}{2}$ .

$\frac{45 y - \frac{27}{2} + \frac{5 \cdot 2}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.7

Combine the numerators over the common denominator.

$\frac{45 y + \frac{- 27 + 5 \cdot 2}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.8

Simplify the numerator.

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Step 2.2.1.8.1

Multiply $5$ by $2$ .

$\frac{45 y + \frac{- 27 + 10}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.8.2

Add $- 27$ and $10$ .

$\frac{45 y + \frac{- 17}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{45 y + \frac{- 17}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.9

Move the negative in front of the fraction.

$\frac{45 y - \frac{17}{2} - 4}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.10

To write $- 4$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{45 y - \frac{17}{2} - 4 \cdot \frac{2}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.11

Combine $- 4$ and $\frac{2}{2}$ .

$\frac{45 y - \frac{17}{2} + \frac{- 4 \cdot 2}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.12

Combine the numerators over the common denominator.

$\frac{45 y + \frac{- 17 - 4 \cdot 2}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.13

Simplify the numerator.

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Step 2.2.1.13.1

Multiply $- 4$ by $2$ .

$\frac{45 y + \frac{- 17 - 8}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.13.2

Subtract $8$ from $- 17$ .

$\frac{45 y + \frac{- 25}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{45 y + \frac{- 25}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.14

Move the negative in front of the fraction.

$\frac{45 y - \frac{25}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15

Simplify the numerator.

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Step 2.2.1.15.1

Factor $5$ out of $45 y - \frac{25}{2}$ .

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Step 2.2.1.15.1.1

Factor $5$ out of $45 y$ .

$\frac{5 (9 y) - \frac{25}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.1.2

Factor $5$ out of $- \frac{25}{2}$ .

$\frac{5 (9 y) + 5 (- \frac{5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.1.3

Factor $5$ out of $5 (9 y) + 5 (- \frac{5}{2})$ .

$\frac{5 (9 y - \frac{5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (9 y - \frac{5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.2

To write $9 y$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{5 (9 y \cdot \frac{2}{2} - \frac{5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.3

Combine $9 y$ and $\frac{2}{2}$ .

$\frac{5 (\frac{9 y \cdot 2}{2} - \frac{5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.4

Combine the numerators over the common denominator.

$\frac{5 (\frac{9 y \cdot 2 - 5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.15.5

Multiply $2$ by $9$ .

$\frac{5 (\frac{18 y - 5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (\frac{18 y - 5}{2})}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.16

Combine $5$ and $\frac{18 y - 5}{2}$ .

$\frac{\frac{5 (18 y - 5)}{2}}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.17

Multiply the numerator by the reciprocal of the denominator.

$\frac{5 (18 y - 5)}{2} \cdot \frac{1}{9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.18

Multiply $\frac{5 (18 y - 5)}{2} \cdot \frac{1}{9}$ .

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Step 2.2.1.18.1

Multiply $\frac{5 (18 y - 5)}{2}$ by $\frac{1}{9}$ .

$\frac{5 (18 y - 5)}{2 \cdot 9} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 2.2.1.18.2

Multiply $2$ by $9$ .

$\frac{5 (18 y - 5)}{18} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (18 y - 5)}{18} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (18 y - 5)}{18} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (18 y - 5)}{18} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$\frac{5 (18 y - 5)}{18} = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3

Solve for $y$ in $\frac{5 (18 y - 5)}{18} = 0$ .

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Step 3.1

Set the numerator equal to zero.

$5 (18 y - 5) = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2

Solve the equation for $y$ .

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Step 3.2.1

Divide each term in $5 (18 y - 5) = 0$ by $5$ and simplify.

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Step 3.2.1.1

Divide each term in $5 (18 y - 5) = 0$ by $5$ .

$\frac{5 (18 y - 5)}{5} = \frac{0}{5}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.1.2

Simplify the left side.

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Step 3.2.1.2.1

Cancel the common factor of $5$ .

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Step 3.2.1.2.1.1

Cancel the common factor.

$\frac{5 (18 y - 5)}{5} = \frac{0}{5}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.1.2.1.2

Divide $18 y - 5$ by $1$ .

$18 y - 5 = \frac{0}{5}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$18 y - 5 = \frac{0}{5}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$18 y - 5 = \frac{0}{5}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.1.3

Simplify the right side.

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Step 3.2.1.3.1

Divide $0$ by $5$ .

$18 y - 5 = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$18 y - 5 = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

$18 y - 5 = 0$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.2

Add $5$ to both sides of the equation.

$18 y = 5$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.3

Divide each term in $18 y = 5$ by $18$ and simplify.

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Step 3.2.3.1

Divide each term in $18 y = 5$ by $18$ .

$\frac{18 y}{18} = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.3.2

Simplify the left side.

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Step 3.2.3.2.1

Cancel the common factor of $18$ .

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Step 3.2.3.2.1.1

Cancel the common factor.

$\frac{18 y}{18} = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 3.2.3.2.1.2

Divide $y$ by $1$ .

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{3 y}{4} + \frac{5}{24}$

Step 4

Replace all occurrences of $y$ with $\frac{5}{18}$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $x = \frac{3 y}{4} + \frac{5}{24}$ with $\frac{5}{18}$ .

$x = \frac{3 (\frac{5}{18})}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $\frac{3 (\frac{5}{18})}{4} + \frac{5}{24}$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Combine $3$ and $\frac{5}{18}$ .

$x = \frac{\frac{3 \cdot 5}{18}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.2

Multiply $3$ by $5$ .

$x = \frac{\frac{15}{18}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.3

Cancel the common factor of $15$ and $18$ .

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Step 4.2.1.1.3.1

Factor $3$ out of $15$ .

$x = \frac{\frac{3 (5)}{18}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.3.2

Cancel the common factors.

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Step 4.2.1.1.3.2.1

Factor $3$ out of $18$ .

$x = \frac{\frac{3 \cdot 5}{3 \cdot 6}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.3.2.2

Cancel the common factor.

$x = \frac{\frac{3 \cdot 5}{3 \cdot 6}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.3.2.3

Rewrite the expression.

$x = \frac{\frac{5}{6}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{\frac{5}{6}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{\frac{5}{6}}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.4

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{5}{6} \cdot \frac{1}{4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.5

Multiply $\frac{5}{6} \cdot \frac{1}{4}$ .

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Step 4.2.1.1.5.1

Multiply $\frac{5}{6}$ by $\frac{1}{4}$ .

$x = \frac{5}{6 \cdot 4} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.1.5.2

Multiply $6$ by $4$ .

$x = \frac{5}{24} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{5}{24} + \frac{5}{24}$

$y = \frac{5}{18}$

$x = \frac{5}{24} + \frac{5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.2

Simplify terms.

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Step 4.2.1.2.1

Combine the numerators over the common denominator.

$x = \frac{5 + 5}{24}$

$y = \frac{5}{18}$

Step 4.2.1.2.2

Add $5$ and $5$ .

$x = \frac{10}{24}$

$y = \frac{5}{18}$

Step 4.2.1.2.3

Cancel the common factor of $10$ and $24$ .

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Step 4.2.1.2.3.1

Factor $2$ out of $10$ .

$x = \frac{2 (5)}{24}$

$y = \frac{5}{18}$

Step 4.2.1.2.3.2

Cancel the common factors.

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Step 4.2.1.2.3.2.1

Factor $2$ out of $24$ .

$x = \frac{2 \cdot 5}{2 \cdot 12}$

$y = \frac{5}{18}$

Step 4.2.1.2.3.2.2

Cancel the common factor.

$x = \frac{2 \cdot 5}{2 \cdot 12}$

$y = \frac{5}{18}$

Step 4.2.1.2.3.2.3

Rewrite the expression.

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

$x = \frac{5}{12}$

$y = \frac{5}{18}$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(\frac{5}{12}, \frac{5}{18})$

Step 6

The result can be shown in multiple forms.

Point Form:

$(\frac{5}{12}, \frac{5}{18})$

Equation Form:

$x = \frac{5}{12}, y = \frac{5}{18}$

Step 7