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Algebra Examples
Step 1
Since is on the right side of the equation, switch the sides so it is on the left side of the equation.
Step 2
Add to both sides of the equation.
Step 3
Add to both sides of the equation.
Step 4
Add and .
Step 5
Step 5.1
Factor out of .
Step 5.1.1
Factor out of .
Step 5.1.2
Raise to the power of .
Step 5.1.3
Factor out of .
Step 5.1.4
Factor out of .
Step 5.2
Factor.
Step 5.2.1
Factor out of .
Step 5.2.1.1
Factor out of .
Step 5.2.1.2
Factor out of .
Step 5.2.1.3
Factor out of .
Step 5.2.2
Remove unnecessary parentheses.
Step 5.3
Rewrite as .
Step 5.4
Since both terms are perfect cubes, factor using the sum of cubes formula, where and .
Step 5.5
Simplify.
Step 5.5.1
Multiply by .
Step 5.5.2
Raise to the power of .
Step 5.6
Factor out of .
Step 5.6.1
Factor out of .
Step 5.6.2
Factor out of .
Step 5.7
Move to the left of .
Step 5.8
Subtract from .
Step 6
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Step 7
Step 7.1
Set equal to .
Step 7.2
Subtract from both sides of the equation.
Step 8
Step 8.1
Set equal to .
Step 8.2
Solve for .
Step 8.2.1
Use the quadratic formula to find the solutions.
Step 8.2.2
Substitute the values , , and into the quadratic formula and solve for .
Step 8.2.3
Simplify.
Step 8.2.3.1
Simplify the numerator.
Step 8.2.3.1.1
Raise to the power of .
Step 8.2.3.1.2
Multiply .
Step 8.2.3.1.2.1
Multiply by .
Step 8.2.3.1.2.2
Multiply by .
Step 8.2.3.1.3
Subtract from .
Step 8.2.3.1.4
Rewrite as .
Step 8.2.3.1.5
Rewrite as .
Step 8.2.3.1.6
Rewrite as .
Step 8.2.3.2
Multiply by .
Step 8.2.4
The final answer is the combination of both solutions.
Step 9
The final solution is all the values that make true.