Algebra Examples

$x + 2 y - z = 6$ $x = 6 - 2 y + z$ $x + 2 y = 6 + z$

Step 1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1

Subtract $2 y$ from both sides of the equation.

$x - z = 6 - 2 y$

$x = 6 - 2 y + z$

$x + 2 y = 6 + z$

Step 1.2

Add $z$ to both sides of the equation.

$x = 6 - 2 y + z$

$x + 2 y = 6 + z$

$x = 6 - 2 y + z$

$x + 2 y = 6 + z$

Step 2

Replace all occurrences of $x$ with $6 - 2 y + z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $x + 2 y = 6 + z$ with $6 - 2 y + z$ .

$(6 - 2 y + z) + 2 y = 6 + z$

$x = 6 - 2 y + z$

Step 2.2

Simplify the left side.

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Step 2.2.1

Combine the opposite terms in $(6 - 2 y + z) + 2 y$ .

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Step 2.2.1.1

Add $- 2 y$ and $2 y$ .

$6 + z + 0 = 6 + z$

$x = 6 - 2 y + z$

Step 2.2.1.2

Add $6 + z$ and $0$ .

$6 + z = 6 + z$

$x = 6 - 2 y + z$

$6 + z = 6 + z$

$x = 6 - 2 y + z$

$6 + z = 6 + z$

$x = 6 - 2 y + z$

$6 + z = 6 + z$

$x = 6 - 2 y + z$

Step 3

Remove any equations from the system that are always true.

$x = 6 - 2 y + z$