Algebra Examples

$\frac{2 x^{2}}{7} - \frac{8 x^{5} + 5 x^{2} y^{2}}{x^{3} + 4 y^{2}}$

Step 1

Factor $x^{2}$ out of $8 x^{5} + 5 x^{2} y^{2}$ .

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Step 1.1

Factor $x^{2}$ out of $8 x^{5}$ .

$\frac{2 x^{2}}{7} - \frac{x^{2} (8 x^{3}) + 5 x^{2} y^{2}}{x^{3} + 4 y^{2}}$

Step 1.2

Factor $x^{2}$ out of $5 x^{2} y^{2}$ .

$\frac{2 x^{2}}{7} - \frac{x^{2} (8 x^{3}) + x^{2} (5 y^{2})}{x^{3} + 4 y^{2}}$

Step 1.3

Factor $x^{2}$ out of $x^{2} (8 x^{3}) + x^{2} (5 y^{2})$ .

$\frac{2 x^{2}}{7} - \frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}}$

Step 2

To write $\frac{2 x^{2}}{7}$ as a fraction with a common denominator, multiply by $\frac{x^{3} + 4 y^{2}}{x^{3} + 4 y^{2}}$ .

$\frac{2 x^{2}}{7} \cdot \frac{x^{3} + 4 y^{2}}{x^{3} + 4 y^{2}} - \frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}}$

Step 3

To write $- \frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$\frac{2 x^{2}}{7} \cdot \frac{x^{3} + 4 y^{2}}{x^{3} + 4 y^{2}} - \frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}} \cdot \frac{7}{7}$

Step 4

Write each expression with a common denominator of $7 (x^{3} + 4 y^{2})$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1

Multiply $\frac{2 x^{2}}{7}$ by $\frac{x^{3} + 4 y^{2}}{x^{3} + 4 y^{2}}$ .

$\frac{2 x^{2} (x^{3} + 4 y^{2})}{7 (x^{3} + 4 y^{2})} - \frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}} \cdot \frac{7}{7}$

Step 4.2

Multiply $\frac{x^{2} (8 x^{3} + 5 y^{2})}{x^{3} + 4 y^{2}}$ by $\frac{7}{7}$ .

$\frac{2 x^{2} (x^{3} + 4 y^{2})}{7 (x^{3} + 4 y^{2})} - \frac{x^{2} (8 x^{3} + 5 y^{2}) \cdot 7}{(x^{3} + 4 y^{2}) \cdot 7}$

Step 4.3

Reorder the factors of $(x^{3} + 4 y^{2}) \cdot 7$ .

$\frac{2 x^{2} (x^{3} + 4 y^{2})}{7 (x^{3} + 4 y^{2})} - \frac{x^{2} (8 x^{3} + 5 y^{2}) \cdot 7}{7 (x^{3} + 4 y^{2})}$

Step 5

Combine the numerators over the common denominator.

$\frac{2 x^{2} (x^{3} + 4 y^{2}) - x^{2} (8 x^{3} + 5 y^{2}) \cdot 7}{7 (x^{3} + 4 y^{2})}$

Step 6

Simplify the numerator.

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Step 6.1

Factor $x^{2}$ out of $2 x^{2} (x^{3} + 4 y^{2}) - x^{2} (8 x^{3} + 5 y^{2}) \cdot 7$ .

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Step 6.1.1

Factor $x^{2}$ out of $2 x^{2} (x^{3} + 4 y^{2})$ .

$\frac{x^{2} (2 (x^{3} + 4 y^{2})) - x^{2} (8 x^{3} + 5 y^{2}) \cdot 7}{7 (x^{3} + 4 y^{2})}$

Step 6.1.2

Factor $x^{2}$ out of $- x^{2} (8 x^{3} + 5 y^{2}) \cdot 7$ .

$\frac{x^{2} (2 (x^{3} + 4 y^{2})) + x^{2} ((- (8 x^{3} + 5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.1.3

Factor $x^{2}$ out of $x^{2} (2 (x^{3} + 4 y^{2})) + x^{2} ((- (8 x^{3} + 5 y^{2})) \cdot 7)$ .

$\frac{x^{2} (2 (x^{3} + 4 y^{2}) + (- (8 x^{3} + 5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.2

Apply the distributive property.

$\frac{x^{2} (2 x^{3} + 2 (4 y^{2}) + (- (8 x^{3} + 5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.3

Multiply $4$ by $2$ .

$\frac{x^{2} (2 x^{3} + 8 y^{2} + (- (8 x^{3} + 5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.4

Apply the distributive property.

$\frac{x^{2} (2 x^{3} + 8 y^{2} + (- (8 x^{3}) - (5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.5

Multiply $8$ by $- 1$ .

$\frac{x^{2} (2 x^{3} + 8 y^{2} + (- 8 x^{3} - (5 y^{2})) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.6

Multiply $5$ by $- 1$ .

$\frac{x^{2} (2 x^{3} + 8 y^{2} + (- 8 x^{3} - 5 y^{2}) \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.7

Apply the distributive property.

$\frac{x^{2} (2 x^{3} + 8 y^{2} - 8 x^{3} \cdot 7 - 5 y^{2} \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.8

Multiply $7$ by $- 8$ .

$\frac{x^{2} (2 x^{3} + 8 y^{2} - 56 x^{3} - 5 y^{2} \cdot 7)}{7 (x^{3} + 4 y^{2})}$

Step 6.9

Multiply $7$ by $- 5$ .

$\frac{x^{2} (2 x^{3} + 8 y^{2} - 56 x^{3} - 35 y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 6.10

Subtract $56 x^{3}$ from $2 x^{3}$ .

$\frac{x^{2} (- 54 x^{3} + 8 y^{2} - 35 y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 6.11

Subtract $35 y^{2}$ from $8 y^{2}$ .

$\frac{x^{2} (- 54 x^{3} - 27 y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 6.12

Factor $27$ out of $- 54 x^{3} - 27 y^{2}$ .

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Step 6.12.1

Factor $27$ out of $- 54 x^{3}$ .

$\frac{x^{2} (27 (- 2 x^{3}) - 27 y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 6.12.2

Factor $27$ out of $- 27 y^{2}$ .

$\frac{x^{2} (27 (- 2 x^{3}) + 27 (- y^{2}))}{7 (x^{3} + 4 y^{2})}$

Step 6.12.3

Factor $27$ out of $27 (- 2 x^{3}) + 27 (- y^{2})$ .

$\frac{x^{2} (27 (- 2 x^{3} - y^{2}))}{7 (x^{3} + 4 y^{2})}$

$\frac{x^{2} \cdot 27 (- 2 x^{3} - y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 7

Simplify with factoring out.

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Step 7.1

Move $27$ to the left of $x^{2}$ .

$\frac{27 \cdot x^{2} (- 2 x^{3} - y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 7.2

Factor $- 1$ out of $- 2 x^{3}$ .

$\frac{27 x^{2} (- (2 x^{3}) - y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 7.3

Factor $- 1$ out of $- y^{2}$ .

$\frac{27 x^{2} (- (2 x^{3}) - (y^{2}))}{7 (x^{3} + 4 y^{2})}$

Step 7.4

Factor $- 1$ out of $- (2 x^{3}) - (y^{2})$ .

$\frac{27 x^{2} (- (2 x^{3} + y^{2}))}{7 (x^{3} + 4 y^{2})}$

Step 7.5

Simplify the expression.

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Step 7.5.1

Rewrite $- (2 x^{3} + y^{2})$ as $- 1 (2 x^{3} + y^{2})$ .

$\frac{27 x^{2} (- 1 (2 x^{3} + y^{2}))}{7 (x^{3} + 4 y^{2})}$

Step 7.5.2

Move the negative in front of the fraction.

$- \frac{(27 x^{2}) (2 x^{3} + y^{2})}{7 (x^{3} + 4 y^{2})}$

Step 7.5.3

Reorder factors in $- \frac{(27 x^{2}) (2 x^{3} + y^{2})}{7 (x^{3} + 4 y^{2})}$ .

$- \frac{27 x^{2} (2 x^{3} + y^{2})}{7 (x^{3} + 4 y^{2})}$