Algebra Examples

$\frac{9 x^{4} - 6 x^{3} + 4 x^{2}}{27 x^{4} + 8 x}$

Step 1

Factor $x^{2}$ out of $9 x^{4} - 6 x^{3} + 4 x^{2}$ .

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Step 1.1

Factor $x^{2}$ out of $9 x^{4}$ .

$\frac{x^{2} (9 x^{2}) - 6 x^{3} + 4 x^{2}}{27 x^{4} + 8 x}$

Step 1.2

Factor $x^{2}$ out of $- 6 x^{3}$ .

$\frac{x^{2} (9 x^{2}) + x^{2} (- 6 x) + 4 x^{2}}{27 x^{4} + 8 x}$

Step 1.3

Factor $x^{2}$ out of $4 x^{2}$ .

$\frac{x^{2} (9 x^{2}) + x^{2} (- 6 x) + x^{2} \cdot 4}{27 x^{4} + 8 x}$

Step 1.4

Factor $x^{2}$ out of $x^{2} (9 x^{2}) + x^{2} (- 6 x)$ .

$\frac{x^{2} (9 x^{2} - 6 x) + x^{2} \cdot 4}{27 x^{4} + 8 x}$

Step 1.5

Factor $x^{2}$ out of $x^{2} (9 x^{2} - 6 x) + x^{2} \cdot 4$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{27 x^{4} + 8 x}$

Step 2

Simplify the denominator.

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Step 2.1

Factor $x$ out of $27 x^{4} + 8 x$ .

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Step 2.1.1

Factor $x$ out of $27 x^{4}$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x (27 x^{3}) + 8 x}$

Step 2.1.2

Factor $x$ out of $8 x$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x (27 x^{3}) + x \cdot 8}$

Step 2.1.3

Factor $x$ out of $x (27 x^{3}) + x \cdot 8$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x (27 x^{3} + 8)}$

Step 2.2

Rewrite $27 x^{3}$ as ${(3 x)}^{3}$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ({(3 x)}^{3} + 8)}$

Step 2.3

Rewrite $8$ as $2^{3}$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ({(3 x)}^{3} + 2^{3})}$

Step 2.4

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 3 x$ and $b = 2$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) ({(3 x)}^{2} - (3 x) \cdot 2 + 2^{2}))}$

Step 2.5

Simplify.

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Step 2.5.1

Apply the product rule to $3 x$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) (3^{2} x^{2} - (3 x) \cdot 2 + 2^{2}))}$

Step 2.5.2

Raise $3$ to the power of $2$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) (9 x^{2} - (3 x) \cdot 2 + 2^{2}))}$

Step 2.5.3

Multiply $3$ by $- 1$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) (9 x^{2} - 3 x \cdot 2 + 2^{2}))}$

Step 2.5.4

Multiply $2$ by $- 3$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) (9 x^{2} - 6 x + 2^{2}))}$

Step 2.5.5

Raise $2$ to the power of $2$ .

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x ((3 x + 2) (9 x^{2} - 6 x + 4))}$

$\frac{x^{2} (9 x^{2} - 6 x + 4)}{x (3 x + 2) (9 x^{2} - 6 x + 4)}$

Step 3

Reduce the expression by cancelling the common factors.

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Step 3.1

Cancel the common factor of $x^{2}$ and $x$ .

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Step 3.1.1

Factor $x$ out of $x^{2} (9 x^{2} - 6 x + 4)$ .

$\frac{x (x (9 x^{2} - 6 x + 4))}{x (3 x + 2) (9 x^{2} - 6 x + 4)}$

Step 3.1.2

Cancel the common factors.

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Step 3.1.2.1

Factor $x$ out of $x (3 x + 2) (9 x^{2} - 6 x + 4)$ .

$\frac{x (x (9 x^{2} - 6 x + 4))}{x ((3 x + 2) (9 x^{2} - 6 x + 4))}$

Step 3.1.2.2

Cancel the common factor.

$\frac{x (x (9 x^{2} - 6 x + 4))}{x ((3 x + 2) (9 x^{2} - 6 x + 4))}$

Step 3.1.2.3

Rewrite the expression.

$\frac{x (9 x^{2} - 6 x + 4)}{(3 x + 2) (9 x^{2} - 6 x + 4)}$

Step 3.2

Cancel the common factor of $9 x^{2} - 6 x + 4$ .

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Step 3.2.1

Cancel the common factor.

$\frac{x (9 x^{2} - 6 x + 4)}{(3 x + 2) (9 x^{2} - 6 x + 4)}$

Step 3.2.2

Rewrite the expression.

$\frac{x}{3 x + 2}$