Algebra Examples

$5 x^{2} + b x + 12 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 5$ , $b = b$ , and $c = 12$ into the quadratic formula and solve for $x$ .

$\frac{- b \pm \sqrt{b^{2} - 4 \cdot (5 \cdot 12)}}{2 \cdot 5}$

Step 3

Simplify.

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Step 3.1

Multiply $- 4 \cdot 5 \cdot 12$ .

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Step 3.1.1

Multiply $- 4$ by $5$ .

$x = \frac{- b \pm \sqrt{b^{2} - 20 \cdot 12}}{2 \cdot 5}$

Step 3.1.2

Multiply $- 20$ by $12$ .

$x = \frac{- b \pm \sqrt{b^{2} - 240}}{2 \cdot 5}$

Step 3.2

Multiply $2$ by $5$ .

$x = \frac{- b \pm \sqrt{b^{2} - 240}}{10}$