Algebra Examples

$h (x) = 4 x - 1$ $g (x) = 2 x + 2$

Step 1

Set up the composite result function.

$h (g (x))$

Step 2

Evaluate $h (2 x + 2)$ by substituting in the value of $g$ into $h$ .

$h (2 x + 2) = 4 (2 x + 2) - 1$

Step 3

Simplify each term.

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Step 3.1

Apply the distributive property.

$h (2 x + 2) = 4 (2 x) + 4 \cdot 2 - 1$

Step 3.2

Multiply $2$ by $4$ .

$h (2 x + 2) = 8 x + 4 \cdot 2 - 1$

Step 3.3

Multiply $4$ by $2$ .

$h (2 x + 2) = 8 x + 8 - 1$

Step 4

Subtract $1$ from $8$ .

$h (2 x + 2) = 8 x + 7$