Algebra Examples

$\log_{3} (27) + \log_{3} (81)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{3} (27 \cdot 81)$

Step 2

Multiply $27$ by $81$ .

$\log_{3} (2187)$

Step 3

Logarithm base $3$ of $2187$ is $7$ .

$7$