Algebra Examples

$\log_{6} (36) + \log_{4} (4) + \log_{3} (\frac{1}{27})$

Step 1

Simplify each term.

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Step 1.1

Logarithm base $6$ of $36$ is $2$ .

$2 + \log_{4} (4) + \log_{3} (\frac{1}{27})$

Step 1.2

Logarithm base $4$ of $4$ is $1$ .

$2 + 1 + \log_{3} (\frac{1}{27})$

Step 1.3

Logarithm base $3$ of $\frac{1}{27}$ is $- 3$ .

$2 + 1 - 3$

Step 2

Simplify by adding and subtracting.

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Step 2.1

Add $2$ and $1$ .

$3 - 3$

Step 2.2

Subtract $3$ from $3$ .

$0$