Algebra Examples

$\frac{2 + 4 (6 + 3)}{2 | 3 - 2 (8 - 1) | - 2 \cdot 7}$

Step 1

Cancel the common factor of $2 + 4 (6 + 3)$ and $2 | 3 - 2 (8 - 1) | - 2 \cdot 7$ .

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Step 1.1

Factor $2$ out of $2$ .

$\frac{2 (1) + 4 (6 + 3)}{2 | 3 - 2 (8 - 1) | - 2 \cdot 7}$

Step 1.2

Factor $2$ out of $4 (6 + 3)$ .

$\frac{2 (1) + 2 (2 (6 + 3))}{2 | 3 - 2 (8 - 1) | - 2 \cdot 7}$

Step 1.3

Factor $2$ out of $2 (1) + 2 (2 (6 + 3))$ .

$\frac{2 (1 + 2 (6 + 3))}{2 | 3 - 2 (8 - 1) | - 2 \cdot 7}$

Step 1.4

Cancel the common factors.

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Step 1.4.1

Factor $2$ out of $2 | 3 - 2 (8 - 1) |$ .

$\frac{2 (1 + 2 (6 + 3))}{2 (| 3 - 2 (8 - 1) |) - 2 \cdot 7}$

Step 1.4.2

Factor $2$ out of $- 2 \cdot 7$ .

$\frac{2 (1 + 2 (6 + 3))}{2 (| 3 - 2 (8 - 1) |) + 2 (- 1 \cdot 7)}$

Step 1.4.3

Factor $2$ out of $2 (| 3 - 2 (8 - 1) |) + 2 (- 1 \cdot 7)$ .

$\frac{2 (1 + 2 (6 + 3))}{2 (| 3 - 2 (8 - 1) | - 1 \cdot 7)}$

Step 1.4.4

Cancel the common factor.

$\frac{2 (1 + 2 (6 + 3))}{2 (| 3 - 2 (8 - 1) | - 1 \cdot 7)}$

Step 1.4.5

Rewrite the expression.

$\frac{1 + 2 (6 + 3)}{| 3 - 2 (8 - 1) | - 1 \cdot 7}$

Step 2

Simplify the numerator.

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Step 2.1

Add $6$ and $3$ .

$\frac{1 + 2 \cdot 9}{| 3 - 2 (8 - 1) | - 1 \cdot 7}$

Step 2.2

Multiply $2$ by $9$ .

$\frac{1 + 18}{| 3 - 2 (8 - 1) | - 1 \cdot 7}$

Step 2.3

Add $1$ and $18$ .

$\frac{19}{| 3 - 2 (8 - 1) | - 1 \cdot 7}$

Step 3

Simplify the denominator.

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Step 3.1

Simplify each term.

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Step 3.1.1

Subtract $1$ from $8$ .

$\frac{19}{| 3 - 2 \cdot 7 | - 1 \cdot 7}$

Step 3.1.2

Multiply $- 2$ by $7$ .

$\frac{19}{| 3 - 14 | - 1 \cdot 7}$

Step 3.2

Subtract $14$ from $3$ .

$\frac{19}{| - 11 | - 1 \cdot 7}$

Step 3.3

The absolute value is the distance between a number and zero. The distance between $- 11$ and $0$ is $11$ .

$\frac{19}{11 - 1 \cdot 7}$

Step 3.4

Multiply $- 1$ by $7$ .

$\frac{19}{11 - 7}$

Step 3.5

Subtract $7$ from $11$ .

$\frac{19}{4}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\frac{19}{4}$

Decimal Form:

$4.75$

Mixed Number Form:

$4 \frac{3}{4}$