Algebra Examples

$3 c (2 c + 2) = 9$

Step 1

Subtract $9$ from both sides of the equation.

$3 c (2 c + 2) - 9 = 0$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$3 c (2 c) + 3 c \cdot 2 - 9 = 0$

Step 2.2

Rewrite using the commutative property of multiplication.

$3 \cdot 2 c \cdot c + 3 c \cdot 2 - 9 = 0$

Step 2.3

Multiply $2$ by $3$ .

$3 \cdot 2 c \cdot c + 6 c - 9 = 0$

Step 2.4

Simplify each term.

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Step 2.4.1

Multiply $c$ by $c$ by adding the exponents.

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Step 2.4.1.1

Move $c$ .

$3 \cdot 2 (c \cdot c) + 6 c - 9 = 0$

Step 2.4.1.2

Multiply $c$ by $c$ .

$3 \cdot 2 c^{2} + 6 c - 9 = 0$

Step 2.4.2

Multiply $3$ by $2$ .

$6 c^{2} + 6 c - 9 = 0$

Step 3

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 4

The standard form is $6 c^{2} + 6 c - 9$ .

$6 c^{2} + 6 c - 9 = 0$

Step 5