Algebra Examples

$(x^{4} - 13 x^{2} + 36) \div (x + 2)$

Step 1

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$({(x^{2})}^{2} - 13 x^{2} + 36) \div (x + 2)$

Step 2

Let $u = x^{2}$ . Substitute $u$ for all occurrences of $x^{2}$ .

$(u^{2} - 13 u + 36) \div (x + 2)$

Step 3

Factor $u^{2} - 13 u + 36$ using the AC method.

Tap for more steps...

Step 3.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $36$ and whose sum is $- 13$ .

$- 9, - 4$

Step 3.2

Write the factored form using these integers.

$(u - 9) (u - 4) \div (x + 2)$

Step 4

Replace all occurrences of $u$ with $x^{2}$ .

$(x^{2} - 9) (x^{2} - 4) \div (x + 2)$

Step 5

Rewrite $9$ as $3^{2}$ .

$(x^{2} - 3^{2}) (x^{2} - 4) \div (x + 2)$

Step 6

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 3$ .

$(x + 3) (x - 3) (x^{2} - 4) \div (x + 2)$

Step 7

Rewrite $4$ as $2^{2}$ .

$(x + 3) (x - 3) (x^{2} - 2^{2}) \div (x + 2)$

Step 8

Factor.

Tap for more steps...

Step 8.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$(x + 3) (x - 3) ((x + 2) (x - 2)) \div (x + 2)$

Step 8.2

Remove unnecessary parentheses.

$(x + 3) (x - 3) (x + 2) (x - 2) \div (x + 2)$

Step 9

Reduce the expression by cancelling the common factors.

Tap for more steps...

Step 9.1

Reduce the expression $(x + 3) (x - 3) (x + 2) (x - 2) \div (x + 2)$ by cancelling the common factors.

Tap for more steps...

Step 9.1.1

Cancel the common factor.

$(x + 3) (x - 3) (x + 2) (x - 2) \div (x + 2)$

Step 9.1.2

Rewrite the expression.

$\frac{(x + 3) (x - 3) (x - 2)}{1}$

Step 9.2

Divide $(x + 3) (x - 3) (x - 2)$ by $1$ .

$(x + 3) (x - 3) (x - 2)$