Algebra Examples

${(2 x - 1)}^{6}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{3} = {(2 x - 1)}^{6}$

Step 2

Use the Binomial Theorem.

$a_{3} = {(2 x)}^{6} + 6 {(2 x)}^{5} \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3

Simplify each term.

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Step 3.1

Apply the product rule to $2 x$ .

$a_{3} = 2^{6} x^{6} + 6 {(2 x)}^{5} \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.2

Raise $2$ to the power of $6$ .

$a_{3} = 64 x^{6} + 6 {(2 x)}^{5} \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.3

Apply the product rule to $2 x$ .

$a_{3} = 64 x^{6} + 6 (2^{5} x^{5}) \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.4

Raise $2$ to the power of $5$ .

$a_{3} = 64 x^{6} + 6 (32 x^{5}) \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.5

Multiply $32$ by $6$ .

$a_{3} = 64 x^{6} + 192 x^{5} \cdot - 1 + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.6

Multiply $- 1$ by $192$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 15 {(2 x)}^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.7

Apply the product rule to $2 x$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 15 (2^{4} x^{4}) {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.8

Raise $2$ to the power of $4$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 15 (16 x^{4}) {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.9

Multiply $16$ by $15$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} {(- 1)}^{2} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.10

Raise $- 1$ to the power of $2$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} \cdot 1 + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.11

Multiply $240$ by $1$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} + 20 {(2 x)}^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.12

Apply the product rule to $2 x$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} + 20 (2^{3} x^{3}) {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.13

Raise $2$ to the power of $3$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} + 20 (8 x^{3}) {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.14

Multiply $8$ by $20$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} + 160 x^{3} {(- 1)}^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.15

Raise $- 1$ to the power of $3$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} + 160 x^{3} \cdot - 1 + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.16

Multiply $- 1$ by $160$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 15 {(2 x)}^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.17

Apply the product rule to $2 x$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 15 (2^{2} x^{2}) {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.18

Raise $2$ to the power of $2$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 15 (4 x^{2}) {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.19

Multiply $4$ by $15$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} {(- 1)}^{4} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.20

Raise $- 1$ to the power of $4$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} \cdot 1 + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.21

Multiply $60$ by $1$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} + 6 (2 x) {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.22

Multiply $2$ by $6$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} + 12 x {(- 1)}^{5} + {(- 1)}^{6}$

Step 3.23

Raise $- 1$ to the power of $5$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} + 12 x \cdot - 1 + {(- 1)}^{6}$

Step 3.24

Multiply $- 1$ by $12$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} - 12 x + {(- 1)}^{6}$

Step 3.25

Raise $- 1$ to the power of $6$ .

$a_{3} = 64 x^{6} - 192 x^{5} + 240 x^{4} - 160 x^{3} + 60 x^{2} - 12 x + 1$