Algebra Examples

$343 a^{6} + \frac{1}{27} y^{9}$

Step 1

Rewrite $343 a^{6}$ as ${(7 a^{2})}^{3}$ .

${(7 a^{2})}^{3} + \frac{1}{27} y^{9}$

Step 2

Rewrite $\frac{1}{27} y^{9}$ as ${(\frac{1}{3} y^{3})}^{3}$ .

${(7 a^{2})}^{3} + {(\frac{1}{3} y^{3})}^{3}$

Step 3

Since both terms are perfect cubes, factor using the sum of cubes formula, $a^{3} + b^{3} = (a + b) (a^{2} - a b + b^{2})$ where $a = 7 a^{2}$ and $b = \frac{1}{3} y^{3}$ .

$(7 a^{2} + \frac{1}{3} y^{3}) ({(7 a^{2})}^{2} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4

Simplify.

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Step 4.1

Combine $\frac{1}{3}$ and $y^{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) ({(7 a^{2})}^{2} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.2

Apply the product rule to $7 a^{2}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (7^{2} {(a^{2})}^{2} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.3

Raise $7$ to the power of $2$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 {(a^{2})}^{2} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.4

Multiply the exponents in ${(a^{2})}^{2}$ .

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Step 4.4.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{2 \cdot 2} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.4.2

Multiply $2$ by $2$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - (7 a^{2}) (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.5

Multiply $7$ by $- 1$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - 7 a^{2} (\frac{1}{3} y^{3}) + {(\frac{1}{3} y^{3})}^{2})$

Step 4.6

Rewrite using the commutative property of multiplication.

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - 7 \cdot \frac{1}{3} a^{2} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.7

Multiply $- 7$ by $\frac{1}{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - 7 (\frac{1}{3}) a^{2} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.8

Combine $- 7$ and $\frac{1}{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} + \frac{- 7}{3} a^{2} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.9

Move the negative in front of the fraction.

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7}{3} a^{2} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.10

Combine $a^{2}$ and $\frac{7}{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{a^{2} \cdot 7}{3} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.11

Move $7$ to the left of $a^{2}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 \cdot a^{2}}{3} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.12

Multiply $7$ by $a^{2}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 a^{2}}{3} y^{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.13

Combine $y^{3}$ and $\frac{7 a^{2}}{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{y^{3} (7 a^{2})}{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.14

Remove parentheses.

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{y^{3} \cdot 7 a^{2}}{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.15

Move $7$ to the left of $y^{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 \cdot y^{3} a^{2}}{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.16

Multiply $7$ by $y^{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + {(\frac{1}{3} y^{3})}^{2})$

Step 4.17

Combine $\frac{1}{3}$ and $y^{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + {(\frac{y^{3}}{3})}^{2})$

Step 4.18

Apply the product rule to $\frac{y^{3}}{3}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + \frac{{(y^{3})}^{2}}{3^{2}})$

Step 4.19

Multiply the exponents in ${(y^{3})}^{2}$ .

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Step 4.19.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + \frac{y^{3 \cdot 2}}{3^{2}})$

Step 4.19.2

Multiply $3$ by $2$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + \frac{y^{6}}{3^{2}})$

Step 4.20

Raise $3$ to the power of $2$ .

$(7 a^{2} + \frac{y^{3}}{3}) (49 a^{4} - \frac{7 y^{3} a^{2}}{3} + \frac{y^{6}}{9})$

Step 4.21

Factor.

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Step 4.21.1

Factor $\frac{1}{9}$ out of each term.

$(7 a^{2} + \frac{y^{3}}{3}) (\frac{1}{9} (441 a^{4} - 21 y^{3} a^{2} + y^{6}))$

Step 4.21.2

Remove unnecessary parentheses.

$(7 a^{2} + \frac{y^{3}}{3}) \frac{1}{9} (441 a^{4} - 21 y^{3} a^{2} + y^{6})$