Algebra Examples

$x (5 - 2 x) + 15 = 0$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$x \cdot 5 + x (- 2 x) + 15 = 0$

Step 2.2

Move $5$ to the left of $x$ .

$5 \cdot x + x (- 2 x) + 15 = 0$

Step 2.3

Rewrite using the commutative property of multiplication.

$5 \cdot x - 2 x \cdot x + 15 = 0$

Step 2.4

Multiply $x$ by $x$ by adding the exponents.

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Step 2.4.1

Move $x$ .

$5 x - 2 (x \cdot x) + 15 = 0$

Step 2.4.2

Multiply $x$ by $x$ .

$5 x - 2 x^{2} + 15 = 0$

Step 3

Reorder $5 x$ and $- 2 x^{2}$ .

$- 2 x^{2} + 5 x + 15 = 0$

Step 4