Algebra Examples

$(4 + ({(2 - 5)}^{2} - 4 {(7 - 5)}^{3} + 2 (\frac{15}{3}))) \sqrt{16}$

Step 1

Simplify each term.

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Step 1.1

Subtract $5$ from $2$ .

$(4 + {(- 3)}^{2} - 4 {(7 - 5)}^{3} + 2 (\frac{15}{3})) \sqrt{16}$

Step 1.2

Raise $- 3$ to the power of $2$ .

$(4 + 9 - 4 {(7 - 5)}^{3} + 2 (\frac{15}{3})) \sqrt{16}$

Step 1.3

Subtract $5$ from $7$ .

$(4 + 9 - 4 \cdot 2^{3} + 2 (\frac{15}{3})) \sqrt{16}$

Step 1.4

Raise $2$ to the power of $3$ .

$(4 + 9 - 4 \cdot 8 + 2 (\frac{15}{3})) \sqrt{16}$

Step 1.5

Multiply $- 4$ by $8$ .

$(4 + 9 - 32 + 2 (\frac{15}{3})) \sqrt{16}$

Step 1.6

Divide $15$ by $3$ .

$(4 + 9 - 32 + 2 \cdot 5) \sqrt{16}$

Step 1.7

Multiply $2$ by $5$ .

$(4 + 9 - 32 + 10) \sqrt{16}$

Step 2

Simplify the expression.

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Step 2.1

Add $4$ and $9$ .

$(13 - 32 + 10) \sqrt{16}$

Step 2.2

Subtract $32$ from $13$ .

$(- 19 + 10) \sqrt{16}$

Step 2.3

Add $- 19$ and $10$ .

$- 9 \sqrt{16}$

Step 2.4

Rewrite $16$ as $4^{2}$ .

$- 9 \sqrt{4^{2}}$

Step 2.5

Pull terms out from under the radical, assuming positive real numbers.

$- 9 \cdot 4$

Step 2.6

Multiply $- 9$ by $4$ .

$- 36$