Algebra Examples

$(9^{2} - 2^{6}) - \sqrt{64} + 36 \div 3 (4)$

Step 1

Simplify each term.

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Step 1.1

Raise $9$ to the power of $2$ .

$81 - 2^{6} - \sqrt{64} + 36 \div 3 \cdot 4$

Step 1.2

Raise $2$ to the power of $6$ .

$81 - 1 \cdot 64 - \sqrt{64} + 36 \div 3 \cdot 4$

Step 1.3

Multiply $- 1$ by $64$ .

$81 - 64 - \sqrt{64} + 36 \div 3 \cdot 4$

Step 1.4

Rewrite $64$ as $8^{2}$ .

$81 - 64 - \sqrt{8^{2}} + 36 \div 3 \cdot 4$

Step 1.5

Pull terms out from under the radical, assuming positive real numbers.

$81 - 64 - 1 \cdot 8 + 36 \div 3 \cdot 4$

Step 1.6

Multiply $- 1$ by $8$ .

$81 - 64 - 8 + 36 \div 3 \cdot 4$

Step 1.7

Divide $36$ by $3$ .

$81 - 64 - 8 + 12 \cdot 4$

Step 1.8

Multiply $12$ by $4$ .

$81 - 64 - 8 + 48$

$81 - 64 - 8 + 48$

Step 2

Simplify by adding and subtracting.

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Step 2.1

Subtract $64$ from $81$ .

$17 - 8 + 48$

Step 2.2

Subtract $8$ from $17$ .

$9 + 48$

Step 2.3

Add $9$ and $48$ .

$57$

$57$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$