Algebra Examples

$x^{2} - 2 x (x - 2) + 5 = 0$

Step 1

To write a polynomial in standard form, simplify and then arrange the terms in descending order.

$a x^{2} + b x + c = 0$

Step 2

Simplify each term.

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Step 2.1

Apply the distributive property.

$x^{2} - 2 x \cdot x - 2 x \cdot - 2 + 5 = 0$

Step 2.2

Multiply $x$ by $x$ by adding the exponents.

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Step 2.2.1

Move $x$ .

$x^{2} - 2 (x \cdot x) - 2 x \cdot - 2 + 5 = 0$

Step 2.2.2

Multiply $x$ by $x$ .

$x^{2} - 2 x^{2} - 2 x \cdot - 2 + 5 = 0$

Step 2.3

Multiply $- 2$ by $- 2$ .

$x^{2} - 2 x^{2} + 4 x + 5 = 0$

Step 3

Subtract $2 x^{2}$ from $x^{2}$ .

$- x^{2} + 4 x + 5 = 0$

Step 4