Algebra Examples

$7 (2 e - 1) - 3 = 6 + 6 e$

Step 1

Move all terms not containing a variable to the right side of the equation.

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Step 1.1

Subtract $7 (2 e - 1)$ from both sides of the equation.

$- 3 = 6 + 6 e - 7 (2 e - 1)$

Step 1.2

Add $3$ to both sides of the equation.

$0 = 6 + 6 e - 7 (2 e - 1) + 3$

Step 1.3

Simplify each term.

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Step 1.3.1

Apply the distributive property.

$0 = 6 + 6 e - 7 (2 e) - 7 \cdot - 1 + 3$

Step 1.3.2

Multiply $2$ by $- 7$ .

$0 = 6 + 6 e - 14 e - 7 \cdot - 1 + 3$

Step 1.3.3

Multiply $- 7$ by $- 1$ .

$0 = 6 + 6 e - 14 e + 7 + 3$

Step 1.4

Add $6$ and $7$ .

$0 = 13 + 6 e - 14 e + 3$

Step 1.5

Add $13$ and $3$ .

$0 = 16 + 6 e - 14 e$

Step 1.6

Subtract $14 e$ from $6 e$ .

$0 = 16 - 8 e$

Step 2

Simplify $16 - 8 \cdot 2.71828182$ .

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Step 2.1

Multiply $- 8$ by $2.71828182$ .

$0 = 16 - 21.74625462$

Step 2.2

Subtract $21.74625462$ from $16$ .

$0 = - 5.74625462$

Step 3

Since $0 \neq - 5.74625462$ , there are no solutions.

No solution