Algebra Examples

$7 (2 e - 1) - 3 = 6 + 6 e$

Step 1

Move all the expressions to the left side of the equation.

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Step 1.1

Subtract $6$ from both sides of the equation.

$7 (2 e - 1) - 3 - 6 = 6 e$

Step 1.2

Subtract $6 e$ from both sides of the equation.

$7 (2 e - 1) - 3 - 6 - 6 e = 0$

$7 (2 e - 1) - 3 - 6 - 6 e = 0$

Step 2

Simplify $7 (2 e - 1) - 3 - 6 - 6 e$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$7 (2 e) + 7 \cdot - 1 - 3 - 6 - 6 e = 0$

Step 2.1.2

Multiply $2$ by $7$ .

$14 e + 7 \cdot - 1 - 3 - 6 - 6 e = 0$

Step 2.1.3

Multiply $7$ by $- 1$ .

$14 e - 7 - 3 - 6 - 6 e = 0$

$14 e - 7 - 3 - 6 - 6 e = 0$

Step 2.2

Subtract $6 e$ from $14 e$ .

$8 e - 7 - 3 - 6 = 0$

Step 2.3

Subtract $3$ from $- 7$ .

$8 e - 10 - 6 = 0$

Step 2.4

Subtract $6$ from $- 10$ .

$8 e - 16 = 0$

$8 e - 16 = 0$

Step 3

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$