代数例

$[\begin{array}{c} - 5 - t & 0 \\ 8 & - 22 \end{array}] = [\begin{array}{c} - 5 & 0 \\ 8 & - 4 y - 2 \end{array}]$

ステップ 1

Write as a linear system of equations.

$- 5 - t = - 5$

$0 = 0$

$8 = 8$

$- 22 = - 4 y - 2$

ステップ 2

Since $8 = 8$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.

代数 例