代数例

$[\begin{array}{c} 3 + t & 0 \\ 8 & - 10 \end{array}] = [\begin{array}{c} - 5 & 0 \\ 8 & - 2 y + 2 \end{array}]$

ステップ 1

Write as a linear system of equations.

$3 + t = - 5$

$0 = 0$

$8 = 8$

$- 10 = - 2 y + 2$

ステップ 2

Since $8 = 8$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.

代数 例