Kalkulus Contoh

$lim_{x \to 0} \sqrt{x^{3} + x^{2}} \sin (\frac{π}{x})$

Langkah 1

Karena $\sqrt{x^{3} + x^{2}} \cdot - 1 \leq \sqrt{x^{3} + x^{2}} \sin (\frac{π}{x}) \leq \sqrt{x^{3} + x^{2}} \cdot 1$ dan $lim_{x \to 0} \sqrt{x^{3} + x^{2}} \cdot - 1 = lim_{x \to 0} \sqrt{x^{3} + x^{2}} \cdot 1 = 0$ , terapkan Teorema Apit.

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