Kalkulus Contoh

$lim_{x \to \infty} \frac{\sin^{2} (x)}{x}$

Langkah 1

Karena $\frac{0}{x} \leq \frac{\sin^{2} (x)}{x} \leq \frac{1}{x}$ dan $lim_{x \to \infty} \frac{0}{x} = lim_{x \to \infty} \frac{1}{x} = 0$ , terapkan Teorema Apit.

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