लीनियर एलजेब्रा उदाहरण

$[\begin{array}{c} 1 & 2 & - 3 \\ - 3 & 1 & 2 \\ 2 & - 3 & 1 \end{array}]$

चरण 1

Perform the row operation $R_{2} = R_{2} + 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 1.1

Perform the row operation $R_{2} = R_{2} + 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 2 & - 3 \\ - 3 + 3 \cdot 1 & 1 + 3 \cdot 2 & 2 + 3 \cdot - 3 \\ 2 & - 3 & 1 \end{array}]$

चरण 1.2

$R_{2}$ को सरल करें.

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 7 & - 7 \\ 2 & - 3 & 1 \end{array}]$

चरण 2

Perform the row operation $R_{3} = R_{3} - 2 R_{1}$ to make the entry at $3, 1$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 2.1

Perform the row operation $R_{3} = R_{3} - 2 R_{1}$ to make the entry at $3, 1$ a $0$ .

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 7 & - 7 \\ 2 - 2 \cdot 1 & - 3 - 2 \cdot 2 & 1 - 2 \cdot - 3 \end{array}]$

चरण 2.2

$R_{3}$ को सरल करें.

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 7 & - 7 \\ 0 & - 7 & 7 \end{array}]$

चरण 3

Multiply each element of $R_{2}$ by $\frac{1}{7}$ to make the entry at $2, 2$ a $1$ .

और स्टेप्स के लिए टैप करें…

चरण 3.1

Multiply each element of $R_{2}$ by $\frac{1}{7}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 2 & - 3 \\ \frac{0}{7} & \frac{7}{7} & \frac{- 7}{7} \\ 0 & - 7 & 7 \end{array}]$

चरण 3.2

$R_{2}$ को सरल करें.

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 1 & - 1 \\ 0 & - 7 & 7 \end{array}]$

चरण 4

Perform the row operation $R_{3} = R_{3} + 7 R_{2}$ to make the entry at $3, 2$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 4.1

Perform the row operation $R_{3} = R_{3} + 7 R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 1 & - 1 \\ 0 + 7 \cdot 0 & - 7 + 7 \cdot 1 & 7 + 7 \cdot - 1 \end{array}]$

चरण 4.2

$R_{3}$ को सरल करें.

$[\begin{array}{c} 1 & 2 & - 3 \\ 0 & 1 & - 1 \\ 0 & 0 & 0 \end{array}]$

चरण 5

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

और स्टेप्स के लिए टैप करें…

चरण 5.1

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 2 \cdot 0 & 2 - 2 \cdot 1 & - 3 - 2 \cdot - 1 \\ 0 & 1 & - 1 \\ 0 & 0 & 0 \end{array}]$

चरण 5.2

$R_{1}$ को सरल करें.

$[\begin{array}{c} 1 & 0 & - 1 \\ 0 & 1 & - 1 \\ 0 & 0 & 0 \end{array}]$