एलजेब्रा उदाहरण

$[\begin{array}{c} 4 & 2 \\ 0 & 1 \end{array}] + [\begin{array}{c} 5 & 9 \\ 8 & 2 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 1

संबंधित तत्वों को जोड़ें.

$[\begin{array}{c} 4 + 5 & 2 + 9 \\ 0 + 8 & 1 + 2 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 2

Simplify each element.

और स्टेप्स के लिए टैप करें…

चरण 2.1

$4$ और $5$ जोड़ें.

$[\begin{array}{c} 9 & 2 + 9 \\ 0 + 8 & 1 + 2 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 2.2

$2$ और $9$ जोड़ें.

$[\begin{array}{c} 9 & 11 \\ 0 + 8 & 1 + 2 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 2.3

$0$ और $8$ जोड़ें.

$[\begin{array}{c} 9 & 11 \\ 8 & 1 + 2 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 2.4

$1$ और $2$ जोड़ें.

$[\begin{array}{c} 9 & 11 \\ 8 & 3 \end{array}] = [\begin{array}{c} 9 & x \\ 8 & 3 \end{array}]$

चरण 3

Write as a linear system of equations.

$9 = 9$

$11 = x$

$8 = 8$

$3 = 3$

चरण 4

Since $3 = 3$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying $11 = x$ .