एलजेब्रा उदाहरण

$[\begin{array}{c} 1 & 2 & 4 \\ 0 & 1 & \frac{6}{7} \end{array}]$

चरण 1

Perform the row operation $R_{1} = R_{1} - 2 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 2 \cdot 0 & 2 - 2 \cdot 1 & 4 - 2 (\frac{6}{7}) \\ 0 & 1 & \frac{6}{7} \end{array}]$

चरण 2

$R_{1}$ को सरल करें.

$[\begin{array}{c} 1 & 0 & \frac{16}{7} \\ 0 & 1 & \frac{6}{7} \end{array}]$