Precálculo Ejemplos

$a = 3 (\cos (15) + i \sin (15))$ , $b = 2 (\cos (10) + i \sin (10))$

Paso 1

Reduce el sistema.

$a = 3 (\cos (15) + i \sin (15)), b = 2 (\cos (10) + i \sin (10))$

Paso 2

Simplifica el lado derecho.

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Paso 2.1

Simplifica $3 (\cos (15) + i \sin (15))$ .

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Paso 2.1.1

Simplifica cada término.

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Paso 2.1.1.1

El valor exacto de $\cos (15)$ es $\frac{\sqrt{6} + \sqrt{2}}{4}$ .

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Paso 2.1.1.1.1

Divide $15$ en dos ángulos donde se conozcan los valores de las seis funciones trigonométricas.

$a = 3 (\cos (45 - 30) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.2

Separa la negación.

$a = 3 (\cos (45 - (30)) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.3

Aplica la diferencia de la razón de los ángulos $\cos (x - y) = \cos (x) \cos (y) + \sin (x) \sin (y)$ .

$a = 3 (\cos (45) \cos (30) + \sin (45) \sin (30) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.4

El valor exacto de $\cos (45)$ es $\frac{\sqrt{2}}{2}$ .

$a = 3 (\frac{\sqrt{2}}{2} \cdot \cos (30) + \sin (45) \sin (30) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.5

El valor exacto de $\cos (30)$ es $\frac{\sqrt{3}}{2}$ .

$a = 3 (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \sin (45) \sin (30) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.6

El valor exacto de $\sin (45)$ es $\frac{\sqrt{2}}{2}$ .

$a = 3 (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \sin (30) + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.7

El valor exacto de $\sin (30)$ es $\frac{1}{2}$ .

$a = 3 (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8

Simplifica $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Paso 2.1.1.1.8.1

Simplifica cada término.

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Paso 2.1.1.1.8.1.1

Multiplica $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Paso 2.1.1.1.8.1.1.1

Multiplica $\frac{\sqrt{2}}{2}$ por $\frac{\sqrt{3}}{2}$ .

$a = 3 (\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.1.1.2

Combina con la regla del producto para radicales.

$a = 3 (\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.1.1.3

Multiplica $2$ por $3$ .

$a = 3 (\frac{\sqrt{6}}{2 \cdot 2} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.1.1.4

Multiplica $2$ por $2$ .

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.1.2

Multiplica $\frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Paso 2.1.1.1.8.1.2.1

Multiplica $\frac{\sqrt{2}}{2}$ por $\frac{1}{2}$ .

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{2 \cdot 2} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.1.2.2

Multiplica $2$ por $2$ .

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6}}{4} + \frac{\sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.1.8.2

Combina los numeradores sobre el denominador común.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i \sin (15))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2

El valor exacto de $\sin (15)$ es $\frac{\sqrt{6} - \sqrt{2}}{4}$ .

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Paso 2.1.1.2.1

Divide $15$ en dos ángulos donde se conozcan los valores de las seis funciones trigonométricas.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i \sin (45 - 30))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.2

Separa la negación.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i \sin (45 - (30)))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.3

Aplica la diferencia de la razón de los ángulos.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\sin (45) \cos (30) - \cos (45) \sin (30)))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.4

El valor exacto de $\sin (45)$ es $\frac{\sqrt{2}}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2}}{2} \cdot \cos (30) - \cos (45) \sin (30)))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.5

El valor exacto de $\cos (30)$ es $\frac{\sqrt{3}}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \cos (45) \sin (30)))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.6

El valor exacto de $\cos (45)$ es $\frac{\sqrt{2}}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \sin (30)))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.7

El valor exacto de $\sin (30)$ es $\frac{1}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8

Simplifica $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Paso 2.1.1.2.8.1

Simplifica cada término.

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Paso 2.1.1.2.8.1.1

Multiplica $\frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2}$ .

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Paso 2.1.1.2.8.1.1.1

Multiplica $\frac{\sqrt{2}}{2}$ por $\frac{\sqrt{3}}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2} \sqrt{3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.1.1.2

Combina con la regla del producto para radicales.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{2 \cdot 3}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.1.1.3

Multiplica $2$ por $3$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{2 \cdot 2} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.1.1.4

Multiplica $2$ por $2$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2} \cdot \frac{1}{2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.1.2

Multiplica $- \frac{\sqrt{2}}{2} \cdot \frac{1}{2}$ .

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Paso 2.1.1.2.8.1.2.1

Multiplica $\frac{1}{2}$ por $\frac{\sqrt{2}}{2}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{2 \cdot 2}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.1.2.2

Multiplica $2$ por $2$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6}}{4} - \frac{\sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.2.8.2

Combina los numeradores sobre el denominador común.

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6} - \sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6} - \sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + i (\frac{\sqrt{6} - \sqrt{2}}{4}))$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.1.3

Combina $i$ y $\frac{\sqrt{6} - \sqrt{2}}{4}$ .

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + \frac{i (\sqrt{6} - \sqrt{2})}{4})$

$b = 2 (\cos (10) + i \sin (10))$

$a = 3 (\frac{\sqrt{6} + \sqrt{2}}{4} + \frac{i (\sqrt{6} - \sqrt{2})}{4})$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.2

Combina fracciones.

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Paso 2.1.2.1

Combina los numeradores sobre el denominador común.

$a = 3 (\frac{\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2}}{4})$

$b = 2 (\cos (10) + i \sin (10))$

Paso 2.1.2.2

Combina $3$ y $\frac{\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2}}{4}$ .

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 2 (\cos (10) + i \sin (10))$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 2 (\cos (10) + i \sin (10))$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 2 (\cos (10) + i \sin (10))$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 2 (\cos (10) + i \sin (10))$

Paso 3

Simplifica el lado derecho.

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Paso 3.1

Simplifica $2 (\cos (10) + i \sin (10))$ .

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Paso 3.1.1

Simplifica cada término.

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Paso 3.1.1.1

Evalúa $\cos (10)$ .

$b = 2 (0.98480775 + i \sin (10))$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

Paso 3.1.1.2

Evalúa $\sin (10)$ .

$b = 2 (0.98480775 + i \cdot 0.17364817)$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

Paso 3.1.1.3

Mueve $0.17364817$ a la izquierda de $i$ .

$b = 2 (0.98480775 + 0.17364817 i)$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 2 (0.98480775 + 0.17364817 i)$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

Paso 3.1.2

Simplifica mediante la multiplicación.

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Paso 3.1.2.1

Aplica la propiedad distributiva.

$b = 2 \cdot 0.98480775 + 2 (0.17364817 i)$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

Paso 3.1.2.2

Multiplica.

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Paso 3.1.2.2.1

Multiplica $2$ por $0.98480775$ .

$b = 1.9696155 + 2 (0.17364817 i)$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

Paso 3.1.2.2.2

Multiplica $0.17364817$ por $2$ .

$b = 1.9696155 + 0.34729635 i$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 1.9696155 + 0.34729635 i$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 1.9696155 + 0.34729635 i$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 1.9696155 + 0.34729635 i$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$

$b = 1.9696155 + 0.34729635 i$

$a = \frac{3 (\sqrt{6} + \sqrt{2} + i \sqrt{6} - i \sqrt{2})}{4}$