Chemie Beispiele

$C u S O_{4} \cdot 0.5 H_{2} O$

Schritt 1

$C u S O_{4} \cdot (0.5 H_{2} O)$ is soluble because most sulfates are soluble except $C a S O_{4}$ , $S r S O_{4}$ , $B a S O_{4}$ , $A g_{2} S O_{4}$ , $H g_{2} S O_{4}$ , and $P b S O_{4}$ .

$C u S O_{4} \cdot (0.5 H_{2} O)$ ist löslich