Algebra Beispiele

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] - ([\begin{array}{c} - 19 & 17 & - 1 \end{array}] + [\begin{array}{c} 14 & 13 & - 2 \end{array}]) = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1

Vereinfache jeden Term.

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Schritt 1.1

Addiere die entsprechenden Elemente.

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] - [\begin{array}{c} - 19 + 14 & 17 + 13 & - 1 - 2 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.2

Simplify each element.

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Schritt 1.2.1

Addiere $- 19$ und $14$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] - [\begin{array}{c} - 5 & 17 + 13 & - 1 - 2 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.2.2

Addiere $17$ und $13$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] - [\begin{array}{c} - 5 & 30 & - 1 - 2 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.2.3

Subtrahiere $2$ von $- 1$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] - [\begin{array}{c} - 5 & 30 & - 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.3

Multipliziere $- 1$ mit jedem Element der Matrix.

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] + [\begin{array}{c} - - 5 & - 1 \cdot 30 & - - 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.4

Vereinfache jedes Element der Matrix.

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Schritt 1.4.1

Mutltipliziere $- 1$ mit $- 5$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] + [\begin{array}{c} 5 & - 1 \cdot 30 & - - 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.4.2

Mutltipliziere $- 1$ mit $30$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] + [\begin{array}{c} 5 & - 30 & - - 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 1.4.3

Mutltipliziere $- 1$ mit $- 3$ .

$[\begin{array}{c} - 8 & - 14 & - 2 x \end{array}] + [\begin{array}{c} 5 & - 30 & 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 2

Addiere die entsprechenden Elemente.

$[\begin{array}{c} - 8 + 5 & - 14 - 30 & - 2 x + 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 3

Simplify each element.

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Schritt 3.1

Addiere $- 8$ und $5$ .

$[\begin{array}{c} - 3 & - 14 - 30 & - 2 x + 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 3.2

Subtrahiere $30$ von $- 14$ .

$[\begin{array}{c} - 3 & - 44 & - 2 x + 3 \end{array}] = [\begin{array}{c} - 3 & - 44 & - 9 \end{array}]$

Schritt 4

Write as a linear system of equations.

$- 3 = - 3$

$- 44 = - 44$

$- 2 x + 3 = - 9$

Schritt 5

Since $- 44 = - 44$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying $- 2 x + 3 = - 9$ .