Algebra Beispiele

$f (x) = {(x^{3} - 2)}^{\frac{1}{5}} + 3$

Schritt 1

Schreibe $f (x) = {(x^{3} - 2)}^{\frac{1}{5}} + 3$ als Gleichung.

$y = {(x^{3} - 2)}^{\frac{1}{5}} + 3$

Schritt 2

Vertausche die Variablen.

$x = {(y^{3} - 2)}^{\frac{1}{5}} + 3$

Schritt 3

Löse nach $y$ auf.

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Schritt 3.1

Schreibe die Gleichung als ${(y^{3} - 2)}^{\frac{1}{5}} + 3 = x$ um.

${(y^{3} - 2)}^{\frac{1}{5}} + 3 = x$

Schritt 3.2

Subtrahiere $3$ von beiden Seiten der Gleichung.

${(y^{3} - 2)}^{\frac{1}{5}} = x - 3$

Schritt 3.3

Potenziere jede Seite der Gleichung mit $5$ , um den gebrochenen Exponenten auf der linken Seite zu eliminieren.

${({(y^{3} - 2)}^{\frac{1}{5}})}^{5} = {(x - 3)}^{5}$

Schritt 3.4

Vereinfache den Exponenten.

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Schritt 3.4.1

Vereinfache die linke Seite.

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Schritt 3.4.1.1

Vereinfache ${({(y^{3} - 2)}^{\frac{1}{5}})}^{5}$ .

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Schritt 3.4.1.1.1

Multipliziere die Exponenten in ${({(y^{3} - 2)}^{\frac{1}{5}})}^{5}$ .

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Schritt 3.4.1.1.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

${(y^{3} - 2)}^{\frac{1}{5} \cdot 5} = {(x - 3)}^{5}$

Schritt 3.4.1.1.1.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 3.4.1.1.1.2.1

Kürze den gemeinsamen Faktor.

${(y^{3} - 2)}^{\frac{1}{5} \cdot 5} = {(x - 3)}^{5}$

Schritt 3.4.1.1.1.2.2

Forme den Ausdruck um.

${(y^{3} - 2)}^{1} = {(x - 3)}^{5}$

Schritt 3.4.1.1.2

Vereinfache.

$y^{3} - 2 = {(x - 3)}^{5}$

Schritt 3.4.2

Vereinfache die rechte Seite.

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Schritt 3.4.2.1

Vereinfache ${(x - 3)}^{5}$ .

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Schritt 3.4.2.1.1

Wende den binomischen Lehrsatz an.

$y^{3} - 2 = x^{5} + 5 x^{4} \cdot - 3 + 10 x^{3} {(- 3)}^{2} + 10 x^{2} {(- 3)}^{3} + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2

Vereinfache jeden Term.

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Schritt 3.4.2.1.2.1

Mutltipliziere $- 3$ mit $5$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 10 x^{3} {(- 3)}^{2} + 10 x^{2} {(- 3)}^{3} + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2.2

Potenziere $- 3$ mit $2$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 10 x^{3} \cdot 9 + 10 x^{2} {(- 3)}^{3} + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2.3

Mutltipliziere $9$ mit $10$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} + 10 x^{2} {(- 3)}^{3} + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2.4

Potenziere $- 3$ mit $3$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} + 10 x^{2} \cdot - 27 + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2.5

Mutltipliziere $- 27$ mit $10$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 5 x {(- 3)}^{4} + {(- 3)}^{5}$

Schritt 3.4.2.1.2.6

Potenziere $- 3$ mit $4$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 5 x \cdot 81 + {(- 3)}^{5}$

Schritt 3.4.2.1.2.7

Mutltipliziere $81$ mit $5$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x + {(- 3)}^{5}$

Schritt 3.4.2.1.2.8

Potenziere $- 3$ mit $5$ .

$y^{3} - 2 = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243$

Schritt 3.5

Löse nach $y$ auf.

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Schritt 3.5.1

Bringe alle Terme, die nicht $y$ enthalten, auf die rechte Seite der Gleichung.

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Schritt 3.5.1.1

Addiere $2$ zu beiden Seiten der Gleichung.

$y^{3} = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243 + 2$

Schritt 3.5.1.2

Addiere $- 243$ und $2$ .

$y^{3} = x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241$

Schritt 3.5.2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$

Schritt 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$

Schritt 5

Überprüfe, ob $f^{- 1} (x) = \sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$ die Umkehrfunktion von $f (x) = {(x^{3} - 2)}^{\frac{1}{5}} + 3$ ist.

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Schritt 5.1

Um die inverse Funktion (Umkehrfunktion) zu prüfen, prüfe ob $f^{- 1} (f (x)) = x$ ist und $f (f^{- 1} (x)) = x$ ist.

Schritt 5.2

Berechne $f^{- 1} (f (x))$ .

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Schritt 5.2.1

Bilde die verkettete Ergebnisfunktion.

$f^{- 1} (f (x))$

Schritt 5.2.2

Berechne $f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3)$ durch Einsetzen des Wertes von $f$ in $f^{- 1}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{{({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.3

Wende den binomischen Lehrsatz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{{({(x^{3} - 2)}^{\frac{1}{5}})}^{5} + 5 {({(x^{3} - 2)}^{\frac{1}{5}})}^{4} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4

Vereinfache Terme.

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Schritt 5.2.4.1

Vereinfache jeden Term.

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Schritt 5.2.4.1.1

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{5}$ .

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Schritt 5.2.4.1.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{{(x^{3} - 2)}^{\frac{1}{5} \cdot 5} + 5 {({(x^{3} - 2)}^{\frac{1}{5}})}^{4} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.1.2

Kürze den gemeinsamen Faktor von $5$ .

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Schritt 5.2.4.1.1.2.1

Kürze den gemeinsamen Faktor.

Schritt 5.2.4.1.1.2.2

Forme den Ausdruck um.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{(x^{3} - 2) + 5 {({(x^{3} - 2)}^{\frac{1}{5}})}^{4} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.2

Vereinfache.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 5 {({(x^{3} - 2)}^{\frac{1}{5}})}^{4} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.3

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{4}$ .

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Schritt 5.2.4.1.3.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 5 {(x^{3} - 2)}^{\frac{1}{5} \cdot 4} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.3.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 5 {(x^{3} - 2)}^{\frac{4}{5}} \cdot 3 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.4

Mutltipliziere $3$ mit $5$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.5

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.4.1.5.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 10 {(x^{3} - 2)}^{\frac{1}{5} \cdot 3} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.5.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 10 {(x^{3} - 2)}^{\frac{3}{5}} \cdot 3^{2} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.6

Potenziere $3$ mit $2$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 10 {(x^{3} - 2)}^{\frac{3}{5}} \cdot 9 + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.7

Mutltipliziere $9$ mit $10$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 10 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.8

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.4.1.8.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 10 {(x^{3} - 2)}^{\frac{1}{5} \cdot 2} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.8.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 10 {(x^{3} - 2)}^{\frac{2}{5}} \cdot 3^{3} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.9

Potenziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 10 {(x^{3} - 2)}^{\frac{2}{5}} \cdot 27 + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.10

Mutltipliziere $27$ mit $10$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{4} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.11

Potenziere $3$ mit $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 5 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 81 + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.12

Mutltipliziere $81$ mit $5$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 3^{5} - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.1.13

Potenziere $3$ mit $5$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 2 + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 243 - 15 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{4} + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.4.2

Addiere $- 2$ und $243$ .

Schritt 5.2.5

Wende den binomischen Lehrsatz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({({(x^{3} - 2)}^{\frac{1}{5}})}^{4} + 4 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3 + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6

Vereinfache Terme.

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Schritt 5.2.6.1

Vereinfache jeden Term.

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Schritt 5.2.6.1.1

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{4}$ .

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Schritt 5.2.6.1.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{1}{5} \cdot 4} + 4 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3 + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.1.2

Kombiniere $\frac{1}{5}$ und $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 4 {({(x^{3} - 2)}^{\frac{1}{5}})}^{3} \cdot 3 + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.2

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.6.1.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 4 {(x^{3} - 2)}^{\frac{1}{5} \cdot 3} \cdot 3 + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.2.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 4 {(x^{3} - 2)}^{\frac{3}{5}} \cdot 3 + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.3

Mutltipliziere $3$ mit $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 6 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.4

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.6.1.4.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 6 {(x^{3} - 2)}^{\frac{1}{5} \cdot 2} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.4.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 6 {(x^{3} - 2)}^{\frac{2}{5}} \cdot 3^{2} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.5

Potenziere $3$ mit $2$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 6 {(x^{3} - 2)}^{\frac{2}{5}} \cdot 9 + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.6

Mutltipliziere $9$ mit $6$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 54 {(x^{3} - 2)}^{\frac{2}{5}} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{3} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.7

Potenziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 54 {(x^{3} - 2)}^{\frac{2}{5}} + 4 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 27 + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.8

Mutltipliziere $27$ mit $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 54 {(x^{3} - 2)}^{\frac{2}{5}} + 108 {(x^{3} - 2)}^{\frac{1}{5}} + 3^{4}) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.1.9

Potenziere $3$ mit $4$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 ({(x^{3} - 2)}^{\frac{4}{5}} + 12 {(x^{3} - 2)}^{\frac{3}{5}} + 54 {(x^{3} - 2)}^{\frac{2}{5}} + 108 {(x^{3} - 2)}^{\frac{1}{5}} + 81) + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.6.2

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 15 (12 {(x^{3} - 2)}^{\frac{3}{5}}) - 15 (54 {(x^{3} - 2)}^{\frac{2}{5}}) - 15 (108 {(x^{3} - 2)}^{\frac{1}{5}}) - 15 \cdot 81 + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.7

Vereinfache.

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Schritt 5.2.7.1

Mutltipliziere $12$ mit $- 15$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 15 (54 {(x^{3} - 2)}^{\frac{2}{5}}) - 15 (108 {(x^{3} - 2)}^{\frac{1}{5}}) - 15 \cdot 81 + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.7.2

Mutltipliziere $54$ mit $- 15$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 15 (108 {(x^{3} - 2)}^{\frac{1}{5}}) - 15 \cdot 81 + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.7.3

Mutltipliziere $108$ mit $- 15$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 15 \cdot 81 + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.7.4

Mutltipliziere $- 15$ mit $81$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{3} - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.8

Wende den binomischen Lehrsatz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({({(x^{3} - 2)}^{\frac{1}{5}})}^{3} + 3 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9

Vereinfache Terme.

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Schritt 5.2.9.1

Vereinfache jeden Term.

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Schritt 5.2.9.1.1

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{3}$ .

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Schritt 5.2.9.1.1.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{1}{5} \cdot 3} + 3 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.1.2

Kombiniere $\frac{1}{5}$ und $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 3 {({(x^{3} - 2)}^{\frac{1}{5}})}^{2} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.2

Multipliziere die Exponenten in ${({(x^{3} - 2)}^{\frac{1}{5}})}^{2}$ .

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Schritt 5.2.9.1.2.1

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 3 {(x^{3} - 2)}^{\frac{1}{5} \cdot 2} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.2.2

Kombiniere $\frac{1}{5}$ und $2$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 3 {(x^{3} - 2)}^{\frac{2}{5}} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.3

Mutltipliziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 3 {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3^{2} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.4

Multipliziere $3$ mit $3^{2}$ durch Addieren der Exponenten.

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Schritt 5.2.9.1.4.1

Bewege $3^{2}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 3^{2} \cdot (3 {(x^{3} - 2)}^{\frac{1}{5}}) + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.4.2

Mutltipliziere $3^{2}$ mit $3$ .

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Schritt 5.2.9.1.4.2.1

Potenziere $3$ mit $1$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 3^{2} \cdot (3 {(x^{3} - 2)}^{\frac{1}{5}}) + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.4.2.2

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 3^{2 + 1} {(x^{3} - 2)}^{\frac{1}{5}} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.4.3

Addiere $2$ und $1$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 3^{3} {(x^{3} - 2)}^{\frac{1}{5}} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.5

Potenziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 27 {(x^{3} - 2)}^{\frac{1}{5}} + 3^{3}) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.1.6

Potenziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 ({(x^{3} - 2)}^{\frac{3}{5}} + 9 {(x^{3} - 2)}^{\frac{2}{5}} + 27 {(x^{3} - 2)}^{\frac{1}{5}} + 27) - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.9.2

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 90 (9 {(x^{3} - 2)}^{\frac{2}{5}}) + 90 (27 {(x^{3} - 2)}^{\frac{1}{5}}) + 90 \cdot 27 - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.10

Vereinfache.

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Schritt 5.2.10.1

Mutltipliziere $9$ mit $90$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 90 (27 {(x^{3} - 2)}^{\frac{1}{5}}) + 90 \cdot 27 - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.10.2

Mutltipliziere $27$ mit $90$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 90 \cdot 27 - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.10.3

Mutltipliziere $90$ mit $27$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2} + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.11

Schreibe ${({(x^{3} - 2)}^{\frac{1}{5}} + 3)}^{2}$ als $({(x^{3} - 2)}^{\frac{1}{5}} + 3) ({(x^{3} - 2)}^{\frac{1}{5}} + 3)$ um.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 (({(x^{3} - 2)}^{\frac{1}{5}} + 3) ({(x^{3} - 2)}^{\frac{1}{5}} + 3)) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.12

Multipliziere $({(x^{3} - 2)}^{\frac{1}{5}} + 3) ({(x^{3} - 2)}^{\frac{1}{5}} + 3)$ aus unter Verwendung der FOIL-Methode.

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Schritt 5.2.12.1

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{1}{5}} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) + 3 ({(x^{3} - 2)}^{\frac{1}{5}} + 3)) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.12.2

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{1}{5}} {(x^{3} - 2)}^{\frac{1}{5}} + {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3 + 3 ({(x^{3} - 2)}^{\frac{1}{5}} + 3)) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.12.3

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{1}{5}} {(x^{3} - 2)}^{\frac{1}{5}} + {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 \cdot 3) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13

Vereinfache und fasse gleichartige Terme zusammen.

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Schritt 5.2.13.1

Vereinfache jeden Term.

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Schritt 5.2.13.1.1

Multipliziere ${(x^{3} - 2)}^{\frac{1}{5}}$ mit ${(x^{3} - 2)}^{\frac{1}{5}}$ durch Addieren der Exponenten.

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Schritt 5.2.13.1.1.1

Wende die Exponentenregel $a^{m} a^{n} = a^{m + n}$ an, um die Exponenten zu kombinieren.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{1}{5} + \frac{1}{5}} + {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 \cdot 3) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13.1.1.2

Vereinige die Zähler über dem gemeinsamen Nenner.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{1 + 1}{5}} + {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 \cdot 3) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13.1.1.3

Addiere $1$ und $1$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{2}{5}} + {(x^{3} - 2)}^{\frac{1}{5}} \cdot 3 + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 \cdot 3) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13.1.2

Bringe $3$ auf die linke Seite von ${(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{2}{5}} + 3 \cdot {(x^{3} - 2)}^{\frac{1}{5}} + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 \cdot 3) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13.1.3

Mutltipliziere $3$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{2}{5}} + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 3 {(x^{3} - 2)}^{\frac{1}{5}} + 9) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.13.2

Addiere $3 {(x^{3} - 2)}^{\frac{1}{5}}$ und $3 {(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 ({(x^{3} - 2)}^{\frac{2}{5}} + 6 {(x^{3} - 2)}^{\frac{1}{5}} + 9) + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.14

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 270 (6 {(x^{3} - 2)}^{\frac{1}{5}}) - 270 \cdot 9 + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.15

Vereinfache.

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Schritt 5.2.15.1

Mutltipliziere $6$ mit $- 270$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 270 \cdot 9 + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.15.2

Mutltipliziere $- 270$ mit $9$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 ({(x^{3} - 2)}^{\frac{1}{5}} + 3) - 241}$

Schritt 5.2.16

Wende das Distributivgesetz an.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 405 \cdot 3 - 241}$

Schritt 5.2.17

Mutltipliziere $405$ mit $3$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 15 {(x^{3} - 2)}^{\frac{4}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 15 {(x^{3} - 2)}^{\frac{4}{5}} - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.18

Subtrahiere $15 {(x^{3} - 2)}^{\frac{4}{5}}$ von $15 {(x^{3} - 2)}^{\frac{4}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 + 0 - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.19

Addiere $x^{3}$ und $0$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 180 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.20

Subtrahiere $180 {(x^{3} - 2)}^{\frac{3}{5}}$ von $90 {(x^{3} - 2)}^{\frac{3}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 270 {(x^{3} - 2)}^{\frac{2}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 810 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.21

Subtrahiere $810 {(x^{3} - 2)}^{\frac{2}{5}}$ von $270 {(x^{3} - 2)}^{\frac{2}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 241 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.22

Subtrahiere $1620 {(x^{3} - 2)}^{\frac{1}{5}}$ von $405 {(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 241 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} - 1215 + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.23

Vereinfache durch Addieren und Subtrahieren.

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Schritt 5.2.23.1

Subtrahiere $1215$ von $241$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 974 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.23.2

Addiere $- 974$ und $2430$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 1456 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} - 2430 + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.23.3

Subtrahiere $2430$ von $1456$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 974 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} + 1215 - 241}$

Schritt 5.2.23.4

Addiere $- 974$ und $1215$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 241 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}} - 241}$

Schritt 5.2.23.5

Subtrahiere $241$ von $241$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 0 - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.23.6

Addiere $x^{3}$ und $0$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 90 {(x^{3} - 2)}^{\frac{3}{5}} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 90 {(x^{3} - 2)}^{\frac{3}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.24

Addiere $- 90 {(x^{3} - 2)}^{\frac{3}{5}}$ und $90 {(x^{3} - 2)}^{\frac{3}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 0 - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.25

Addiere $x^{3}$ und $0$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 540 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 810 {(x^{3} - 2)}^{\frac{2}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.26

Addiere $- 540 {(x^{3} - 2)}^{\frac{2}{5}}$ und $810 {(x^{3} - 2)}^{\frac{2}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 270 {(x^{3} - 2)}^{\frac{2}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.27

Subtrahiere $270 {(x^{3} - 2)}^{\frac{2}{5}}$ von $270 {(x^{3} - 2)}^{\frac{2}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 0 - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.28

Addiere $x^{3}$ und $0$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 1215 {(x^{3} - 2)}^{\frac{1}{5}} + 2430 {(x^{3} - 2)}^{\frac{1}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.29

Addiere $- 1215 {(x^{3} - 2)}^{\frac{1}{5}}$ und $2430 {(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 1215 {(x^{3} - 2)}^{\frac{1}{5}} - 1620 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.30

Subtrahiere $1620 {(x^{3} - 2)}^{\frac{1}{5}}$ von $1215 {(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} - 405 {(x^{3} - 2)}^{\frac{1}{5}} + 405 {(x^{3} - 2)}^{\frac{1}{5}}}$

Schritt 5.2.31

Addiere $- 405 {(x^{3} - 2)}^{\frac{1}{5}}$ und $405 {(x^{3} - 2)}^{\frac{1}{5}}$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3} + 0}$

Schritt 5.2.32

Addiere $x^{3}$ und $0$ .

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = \sqrt[3]{x^{3}}$

Schritt 5.2.33

Ziehe Terme von unter der Wurzel heraus unter der Annahme reeller Zahlen.

$f^{- 1} ({(x^{3} - 2)}^{\frac{1}{5}} + 3) = x$

Schritt 5.3

Berechne $f (f^{- 1} (x))$ .

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Schritt 5.3.1

Bilde die verkettete Ergebnisfunktion.

$f (f^{- 1} (x))$

Schritt 5.3.2

Berechne $f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241})$ durch Einsetzen des Wertes von $f^{- 1}$ in $f$ .

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {({(\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241})}^{3} - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3

Vereinfache jeden Term.

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Schritt 5.3.3.1

Schreibe ${\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}}^{3}$ als $x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241$ um.

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Schritt 5.3.3.1.1

Benutze $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ , um $\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$ als ${(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241)}^{\frac{1}{3}}$ neu zu schreiben.

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {({({(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241)}^{\frac{1}{3}})}^{3} - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.1.2

Wende die Potenzregel an und multipliziere die Exponenten, ${(a^{m})}^{n} = a^{m n}$ .

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {({(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241)}^{\frac{1}{3} \cdot 3} - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.1.3

Kombiniere $\frac{1}{3}$ und $3$ .

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {({(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241)}^{\frac{3}{3}} - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.1.4

Kürze den gemeinsamen Faktor von $3$ .

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Schritt 5.3.3.1.4.1

Kürze den gemeinsamen Faktor.

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {({(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241)}^{\frac{3}{3}} - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.1.4.2

Forme den Ausdruck um.

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {((x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241) - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.1.5

Vereinfache.

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241 - 2)}^{\frac{1}{5}} + 3$

Schritt 5.3.3.2

Subtrahiere $2$ von $- 241$ .

$f (\sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}) = {(x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243)}^{\frac{1}{5}} + 3$

Schritt 5.4

Da $f^{- 1} (f (x)) = x$ und $f (f^{- 1} (x)) = x$ gleich sind, ist $f^{- 1} (x) = \sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$ die inverse Funktion (Umkehrfunktion) von $f (x) = {(x^{3} - 2)}^{\frac{1}{5}} + 3$ .

$f^{- 1} (x) = \sqrt[3]{x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 241}$